Hello folks,
I'm facing a frustrating problem as, to me, my approach appears straight forward and therefore watertight. It is as follows:
As apparent in the attached file, the range doesn't work for both. One array display (VA) appears to stop at the index of its own array (at 100) instead at the index as defined by i (145). Moreover, the average is biased.
Weird!?
The way I see it, the subset VA and the average array mVA should start and stop at the same index. Perhaps this is the culprit. Does anybody have an idea?
Thanks in advance for any help
Raiko
Several things are happening here.
first off, your variable mVA doesn't need to be an array--the mean of an array is a single number. Mathcad is perfectly happy plotting a single number against a range variable. (Try it!)
Second, the reason your mean value seems skewed is because there are a large number of values clustered at the low end. (histogram is a great function for seeing the way data is distributed. Researching this problem led me to discover another problem:
you define x0 and x1 as the trim points for your data--that's a good idea, it lets you change your trims without risking altering the submatrix function call. But when you get below the submatrix function VA is an array that starts at index 0. So when you plot VA[i against i, you're discarding the front 46 points of VA.
I plotted Y<0> against Y<1> (second column against first). Your data shifts at about index 85. When I made x0 = 85, the mean value got healthy, but the circles dissappeared from the plot. Why? Because VA is now 145-85 = 60 elements long, so VA[85 doesn't exist.
I've done some mods, made some notes. Good Luck!
Thank you Fred!
one problem is that each array starts at ist own index, which I managed to overecome by using my start and stop values on the diagram so that the measurement data and the mean begin at the same point.
And thank you for your helpful hints as well!
Raiko
You could use the "Subvector function" to extract your data.
See attached image.
Mike
Your problem occurs because array indicies always start at the value of ORIGIN, which by default is 0. That is true regardless of whether or not you specifically assign values to all the elements when you create the array, or whether the array was created from a larger array using submatrix.
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Hello Jean,
for the life of me - I don't get it. I haven't changed anything, simply shut off my computer over night and this morning: Hogwarts!
Yesterday, there was an offset which I couldn't fix. However, this morning, upon opening the MC document everything was as it should be. Both point series (data and averages) started at the same point. Is this a MC glitch or some windows bug?
Anyway, folks. Thank you for your time
Raiko
Raiko,
My interpretation was that you wanted to plot the mean all along the X at every of the indices. That's only how to plot it. Thus you will have the data around the mean as an artificial Cartesian X. You can have it as a continuous line or points. The bar plot is supplementary and superfluous information.
Jean
Hello Jean,
almost correct.
I wanted to display the average value as a line along with the data points in a cartesian graph. For this I extracted a subset of data points from the original data, since I din't need the start up values of the wind tunnel.
I chose, say, data starting at point 55 and cut off at, say, 155. The new data arry started its index at 0 whereas the calculated average began its display in the graph at 55. Hence, the two data sets started at different points in the graph.
I fixed this, by adding the start value of 55 to the new data arrays index. Therefore, they started at the same point on the graph.
x:=(55,155)
newdata:=submatrix(data,xo,x1,0,0)
average:=mean(newdata)
i:=0..last(newdata)
In the graph I did:
newdata(i+xo) over i
and
average over i
Thanks for your input
Raiko
Raiko,
Why don't you post your worksheet, so it is clear to the members who tried to help, what you where after.
Mike
Mike,
you can find a worksheet (MC 11) at the very first posting of this post
Raiko
Raiko Milanovic wrote:
Mike,
you can find a worksheet (MC 11) at the very first posting of this post
Raiko
Raiko,
I meant your completed project.
Mike
Mike,
I'm sorry but I'm afraid I can't do that 😉 And as I said, over night, by some miracolous quirk perhaps, everything turned out to work right.
Raiko
P.S.
Forgot to attach the new worksheet. Mea culpa
Raiko Milanovic wrote:
Mike,
I'm afraid I can't do that. And as I said, over night, by some miracolous quirk perhaps, everything turned out to work right.
Raiko
Raiko,
If your is work is confidential you can always post an image of the solution, just to give an idea of what you where trying to achieve. Otherwise, what is the point of forum members taking their time to help when they don't have the solution at the end.
This thread will become worthless to new forum members trying to understand Mathcad if there is no end solution.
Mike