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Cornel19-Tanzanite
19-Tanzanite
April 2, 2024
Solved

Plotting failed when defining with inequality

  • April 2, 2024
  • 4 replies
  • 2306 views

Hi,

Why is not possible to plot like below?

Cornel_0-1712043765628.png

 

    Best answer by ttokoro

    image.pngimage.pngimage.pngimage.png

    4 replies

    ttokoro
    21-Topaz I
    ttokoro21-Topaz IAnswer
    21-Topaz I
    April 2, 2024

    image.pngimage.pngimage.pngimage.png

    t.t.
      A
      AlanStevens19-Tanzanite
      19-Tanzanite
      April 2, 2024

      Deleted

      L
      LucMeekes23-Emerald IV
      23-Emerald IV
      April 2, 2024

      The answer to your question:

      Because x/a is a scalar when f(x,a) is called through a plot and you cannot compare a scalar with a range.

       

      Success!

      Luc

      W
      Werner_E25-Diamond I
      25-Diamond I
      April 3, 2024

      Here are my 2 cents worth

      Werner_E_1-1712154014875.png

       

        C
        Cornel19-TanzaniteAuthor
        19-Tanzanite
        April 4, 2024

        How can be made for this @ttokoro 

        Cornel_2-1712222750930.png

         

        Cornel_7-1712222933883.png

         

        Cornel_4-1712222777468.png

        An how to see when, at what position x/a=0.5, 1, 1.5, 2, etc... as there are 10000 elements...

        Cornel_5-1712222836773.png

        Cornel_6-1712222857080.png

         

         

         

        ttokoro
        21-Topaz I
        ttokoro21-Topaz I
        21-Topaz I
        April 4, 2024

        mod condition does not match. So return no data. Not last(x) but last(p). Add else condition.

         

        image.pngimage.pngimage.png

        t.t.
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