On 7/23/2009 4:05:05 AM, Tom_Gutman wrote:
>eq1 you already have.
What I have the current (I) as a function of (Iph, V, I0, Rs, Rsh, n). What I am looking for is the series resistance Rs as a function of (Iph, I, V, I0, Rsh, n), and also the Source Voltage V as a function of (Iph, I, I0, Rs, Rsh, n)
>eq2 and eq3 are probably wrong, as
>they imply current in
>different directions through
>the diode and the shunt.
For dark I-V, the source voltage is greater than the junction potential. It is a good idea to set Iph=0 for dark I-V, however, junction potential is higher than the source voltage for light I-V, and smaller than V for dark I-V.