This may end up being a very simple question for some of you advanced folks. I have been using Mathcad for years, but not always at a great depth, and somewhat sporadically.
Anyhow, I was working through some circuits in the s-domain, and MathCad works really well here to quickly narrow down the equations...certainly faster than by hand.
I have attached the file with my question at the very bottom of of the calculations.
I would really like to solve this circuit for Vo/Vi to arrive at the s-domain transfer function. Is there a one-step solver in Mathcad for this? I know how to use the symbolic solver to find a solution for any single variable, but wondering if there is a way to find the expression for Vo/Vi?
Please don't laugh too hard if I'm missing something obvious through my ignorance. I have hunted through Mathcad's help and some of the other community entries out here and have not found anything like this.
Solved! Go to Solution.
Doh! Never mind...I see that I have an extra term in the numerator that is screwing me up. This circuit has offset and I missed this term before writing my question. My mistake.
Anyhow, faults aside with my initial question, is there a way to directly solve for an expression like Vo/Vi if I didn't have this extra term?
Werner, this solution has given me a powerful tool in my MathCad arsenal, and is exactly the help I needed in properly using MathCad for this solution. Thanks for taking the time to share!
-MF-, Very sorry I have not been available to post a circuit...my priorities were shifted to a different project and I have not been able to get back to this. As I said, I found a couple of errors in my original equation, but with my most recent solution, it seems to track the actual circuit. If I get the chance, I will still come back and post to satisfy your (and my) curiosity.
Yes, of course. I found an error in my initial calculations, but will fix it and re-send with a pic of the circuit. I am away from the office today, but will attempt to put something together for you here. Thank you.