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Wacky datafit problem

LarryBaxter
4-Participant

Wacky datafit problem

It seems simple, but for some reason (probably the normal one, lack of math chops) I'm having trouble with this datafit problem...

...Larry

ACCEPTED SOLUTION

Accepted Solutions

Larry Baxter wrote:

Thanks, Fred,

Help me follow what you've done. How does Ssk work? A symbolic solution must input only Sk, it can't use k

because the function that corrects the error gets only Sk as an input. Aren't you using k in your solve statement?

I think I may have a solution when I can graph a correction factor vs. Sk and match my error term K*Pk^2.

...Confused

Some of my terminology was confusing. See if the attached is any easier to understand.

Fred

View solution in original post

8 REPLIES 8

If you know that the relationship between S and P is of the form S = P - K*P^2 you can treat this as a quadratic equation in P and solve for P. One of the two solutions will give you the function conatining S and K that you need.

Alan

Thanks, Alan,

This doesn't seem to work, I don't know exactly why. We're not exactly solving a quadratic (and when you" solve a quadratic", don't you have an equation with one variable?) we're correcting its effect. Fred's post looks like it may work, if I could only understand it, but Fred's post seems to use k in its solution and we can''t use k (we don't know it), just Sk.

I think I will have a solution when I can graph a correction factor vs. Sk and match my error term K*Pk^2...

...L

See if the attached helps.

Alan

Symbolic solution

Thanks, Fred,

Help me follow what you've done. How does Ssk work? A symbolic solution must input only Sk, it can't use k

because the function that corrects the error gets only Sk as an input. Aren't you using k in your solve statement?

I think I may have a solution when I can graph a correction factor vs. Sk and match my error term K*Pk^2.

...Confused

Larry Baxter wrote:

Thanks, Fred,

Help me follow what you've done. How does Ssk work? A symbolic solution must input only Sk, it can't use k

because the function that corrects the error gets only Sk as an input. Aren't you using k in your solve statement?

I think I may have a solution when I can graph a correction factor vs. Sk and match my error term K*Pk^2.

...Confused

Some of my terminology was confusing. See if the attached is any easier to understand.

Fred

AHA!

I got it now. Thanks!

...L

Fred,

Can we chat offline?

larry@capsense.com

Thanks!

...L

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