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asymptote + odesolve

ValeryOchkov
24-Ruby IV

asymptote + odesolve

Is there a way to find an asymptote of a function created by the Odesolve function

as.png

ACCEPTED SOLUTION

Accepted Solutions
LucMeekes
23-Emerald III
(To:ValeryOchkov)

Thank you.

I think it's a great honour to be named second in place after Christiaan Huygens.

Luc

View solution in original post

27 REPLIES 27
LucMeekes
23-Emerald III
(To:ValeryOchkov)

Hi Valery,

The right-sided asymptote is:

Provided you make sure that F is the point on the y-axis where your focus lies.

In your case F would be -10 (mm).

To get a two-sided asymptote, just replace x with sqrt(x^2).

This plot was made with dimensionless numbers, F= -3, n= sqrt(2).

Regards,

Luc

Thanks, Luc.

Happy NY!

But I think about the red function, not black.

Val

LucMeekes
23-Emerald III
(To:ValeryOchkov)

Hi Valery,

The asymptote I gave IS about the y1 function, not the y2....

Note that for the black function, the asymptote goes through (0,-10mm), whereas the y1 asymptote goes through (0,-10/3) for your values of F=1 cm=10 mm and n=2 according to the function I provided: F/ (n+ 1)= -10/ 3.

Luc

LucMeekes написал(а):

Hi Valery,

The asymptote I gave IS about the y1 function, not the y2....

Luc

And what is an analytical view of this function?

LucMeekes
23-Emerald III
(To:ValeryOchkov)

Ok Valery, here it comes:

Well you know how to solve it numerically, using Odesolve.

I give you the symbolic solution:

An example with F= -1, n=sqrt(2):

To find the asymptote:

Regards,

Luc

Thanks, Luc!

Now I know two man from NL

  1. Christiaan Huygens - Wikipedia
  2. Luc Meekes

Fig-7-Lens-odesolve-Wolfram-Parabola.png

LucMeekes
23-Emerald III
(To:ValeryOchkov)

Thank you.

I think it's a great honour to be named second in place after Christiaan Huygens.

Luc

LucMeekes написал(а):

Thank you.

I think it's a great honour to be named second in place after Christiaan Huygens.

Luc

About it in my article - http://twt.mpei.ac.ru/ochkov/Mirror-Lens-macket.pdf

And what is the formula for y(x, F, n) at the case not n=sin a/sin b - for n=a/b?

LucMeekes
23-Emerald III
(To:ValeryOchkov)

Is this a physical reality?

LucMeekes написал(а):

Is this a physical reality?

At little angles! See plots avove!

This is a solution of one DE!

RichardJ
19-Tanzanite
(To:LucMeekes)

Hi Luc

Could you post the worksheet for that?

Thanks.

I join the request too.

LucMeekes
23-Emerald III
(To:RichardJ)

Hi Rich,

Here you are.

It's Mathcad 11.     I suspect some things will not work in other versions.

Luc

RichardJ
19-Tanzanite
(To:LucMeekes)

Thanks.

You are correct. A lot of the symbolic stuff does not work with the Mupad engine. If I find the time I'll see if I can fix it.

From my future article - sorry - Google translation:

We used two methods for solving optical problems - numerically using Mathcad-function Odesolve and analytical through the site wolfralpha.com. But there is a third (crafty and lazy) way of solving such problems. You can place a problem on the site PTC Community/Mathcad and wait for it someone decides. Thus it was obtained "terrible" formula for y1s (x), placed in the center of the figure 7. It is calculated profile of the focusing lens without changing their angles of the sinuses. This formula (complex analytic solution of a differential equation) led one user Mathcad from Holland - the birthplace of the great Christian Huygens, who made a great contribution to the development of optics - see. https://community.ptc.com/t5/PTC-Mathcad/asymptote-odesolve/td-p/183281. This user Mathcad (Luc Meekes) was the good old 11th version of the engine with a character from the Maple, and not from the MuPAD, which made it possible to solve the problem.

Luc,

The result of the calculation in Mathcad 15 M045 version you can see in the attached PDF file.

LucMeekes
23-Emerald III
(To:VladimirN)

Thanks.

You can surely understand how happy I am with Mathcad 11.

Luc

LucMeekes написал(а):

Thanks.

You can surely understand how happy I am with Mathcad 11.

Luc

You can surely understand how happy I am with... Luc and his Mathcad 11.

Val

One partial case of the Luk's formula ( from one Russian optic hand book - https://mipt.ru/dasr/upload/89a/f_3kf3p7-arphh81ii9w.pdf )

Simple-Formula.png

One more solution thru a tautochronism

4-Lens-Tau.png

LucMeekes
23-Emerald III
(To:ValeryOchkov)

Great, Valery!

I am convinced.

Luc

I think it is an errror of numrerical calculation.

The question is.

Is it a one branch of a hyperbola?

ValeryOchkov написал(а):

I think it is an errror of numrerical calculation.

The question is.

Is it a one branch of a hyperbola?

Yes, hyperbola! One question - why not simplify h*n=h*n

hyperbola.png

Is any physical in second branch of the hyperbola?

A parabola

A circle

... and a parabola (a mirror)

parabola.png

One simple example

But how can we show that two function y_PC and y_VO are equal? Like sin and tan*cos.

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