Hi
How can I use if function when I have two statement shall be valid at the same time:
For example:
y=0 if x=5 and z=10
y=1 otherwise
How can I replace "and"?
Thanks
Solved! Go to Solution.
Like so.
Sorry, the and function can be found on the Boolean toolbar or by Ctrl+&.
if function not operator:
y:=if(x=5 ^ z=10, 0, 1)
or
y:=if(x=5, if((z=10, 0,), 1)
Of course Valery. There is more thanone way to skin a cat
Mike Armstrong wrote:
Of course Valery. There is more thanone way to skin a cat
But only one is correct
Do you know differents:
y:=if(x=5 ^ z=10, 0, 1)
y:=if(x=5, if((z=10, 0, 1), 1)
y:=if(z=10 ^ x=5, 0, 1)
y:=if(z=10, if((x=5, 0, 1), 1)
You sure!!!!
If x not equal 5 we do not need to check z=10: if..(if.. is more correct than ... and ...
Valery Ochkov wrote:
If x not equal 5 we do not need to check z=10: if..(if.. is more correct than ... and ...
Its sure equally correct but it may be a bit more efficient.
Werner Exinger wrote:
Valery Ochkov wrote:
If x not equal 5 we do not need to check z=10: if..(if.. is more correct than ... and ...
Its sure equally correct but it may be a bit more efficient.
Why I point it!?
Two days ego I have corrected one function in WaterSteamPro set - I have replaced the end operator on two if/ Now we have no error in it!
Why I point it!?
Two days ego I have corrected one function in WaterSteamPro set - I have replaced the end operator on two if/ Now we have no error in it!
Not sure what you mean by "replace end operator".
When evaluating a combined boolean expression, Mathcad uses shortcut evaluation - sometimes also calles short-circuit evaluation. That means if we have ... A AND B .... and A is already false, B is not evaluated at all. This is very often convenient but its dangerous because as far as I know its not documented so PTC may change that behaviour without notice. So the order of the operands in a logical combined expression matters and you are on the safe side, if you use nested if's. Not considering this may have been the casuse for the error in your sheet.