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polar transformation

gLanzer
1-Visitor

polar transformation

hi guys,

new to mathcad (trial license ver15.0)

Is there a way to convert a complex function to its polar form easily?

Say, a+bi >> sqrt(a^2+b^2) angle: atan(b/a)

Also, is there an easy way to find and assign a variable the conjugate of the complex function (without having to retype all the way)

attached is a simple problem (err solution) which i made.

notice that i have to rewrite just to get the conjugate..

and i can't outrightly transform it to phasor..

thanks..

ACCEPTED SOLUTION

Accepted Solutions
StuartBruff
23-Emerald III
(To:gLanzer)

Is there a way to convert a complex function to its polar form easily?

Say, a+bi >> sqrt(a^2+b^2) angle: atan(b/a)

Also, is there an easy way to find and assign a variable the conjugate of the complex function (without having to retype all the way)

attached is a simple problem (err solution) which i made.

notice that i have to rewrite just to get the conjugate..

and i can't outrightly transform it to phasor..

thanks..

Yes. Go to Help and search for the word 'polar'. From the results, select the page 'functions for complex numbers'; this describes the arg function and modulus function. Then goto the linked Quicksheet "Complex Numbers: Polar Notation". This gives examples of their use and gives a pair of (user-defined) functions that handle transformation between the polar and rectangular forms.

You can get the complex conjugate by using the built-in conjugate operator (key stroke " in M13).

As an aside, it is generally better to post a worksheet rather than a pdf file - save somebody the effort of typing in what they see and 'print outs' can mask subtle errors, such as implicit multiplication or incorrect choice of index type (ie, index v literal). Ideally, post the worksheet in the version you use and the earliest version Mathcad will let you save as (the latter gives you a much wider audience as Mathcad worksheet format s are not generally backward compatible), eg Mathcad 11 will not read Mathcad 13 xmcd files).

View solution in original post

4 REPLIES 4
StuartBruff
23-Emerald III
(To:gLanzer)

Is there a way to convert a complex function to its polar form easily?

Say, a+bi >> sqrt(a^2+b^2) angle: atan(b/a)

Also, is there an easy way to find and assign a variable the conjugate of the complex function (without having to retype all the way)

attached is a simple problem (err solution) which i made.

notice that i have to rewrite just to get the conjugate..

and i can't outrightly transform it to phasor..

thanks..

Yes. Go to Help and search for the word 'polar'. From the results, select the page 'functions for complex numbers'; this describes the arg function and modulus function. Then goto the linked Quicksheet "Complex Numbers: Polar Notation". This gives examples of their use and gives a pair of (user-defined) functions that handle transformation between the polar and rectangular forms.

You can get the complex conjugate by using the built-in conjugate operator (key stroke " in M13).

As an aside, it is generally better to post a worksheet rather than a pdf file - save somebody the effort of typing in what they see and 'print outs' can mask subtle errors, such as implicit multiplication or incorrect choice of index type (ie, index v literal). Ideally, post the worksheet in the version you use and the earliest version Mathcad will let you save as (the latter gives you a much wider audience as Mathcad worksheet format s are not generally backward compatible), eg Mathcad 11 will not read Mathcad 13 xmcd files).

Check first your formulas and attach a work sheet with a circuit diagram.

jmG

gLanzer
1-Visitor
(To:gLanzer)

sorry for the late reply..

attached are the problem and the mathcad file..

Sorry, no collab does homework, use your book.

Comments:

1. Why enlarge a scanned image from book ?

2. The quiz is that there is no answer because there is no question.

Alternating sources have no polarity.

MCADunk_1.gif

Can't you parallel the resistive load and the inductive loads ?

Maybe not because the resistive load is just heating the birds on the line.

Invent some resistive load and work by the examples in the book.

If cos f is 0.8575 and not the same as cos f Z, can you conclude the

resistive load ? Can you check if pf 0.8575 is cos f for Z.

Can't open your Mathcad version. [jmG]

jmG

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