How to Parse XML array?

[sarathi]

Hi

I need to Parse the Following XML File

<?xml version="1.0" encoding="UTF-8"?>

-<readings xmlns="http://cyantechnology.com/dean/v1">

<link rel="reading" method="get" href="https://amrindia38.dev.cyanconnode.com:8000/v1/readings/e37ae24c-926d-4876-ac6e-2f90b60e78f6"/>

<link rel="reading" method="get" href="https://url1.com:8000/v1/readings/c5ab20f7-c120-4ac1-8ad7-e09593806e82"/>

<link rel="reading" method="get" href="https://url1.com:8000/v1/readings/5a61362a-f30d-4f6e-8358-eb714d209494"/>

<link rel="reading" method="get" href="https://url1.com:8000/v1/readings/9112421c-2f0b-49e1-8de3-4aeab1ffe6b3"/>

<link rel="reading" method="get" href="https://url1.com:8000/v1/readings/e135fe17-0421-404c-ad8a-71c880edfa09"/>

</readings>

I need to get all href from the above XML Array(Link)....

[pgrodowski]

Hello,

I am not sure if you already have a variable that contains the xml in javascript, if you do, you could get the value of all href attributes using a loop similar to the sample below, xmlDoc is the variable containing the xml, results will contain the href attribute values separated with line breaks, links is a buffer used to further process the link tags:

var links, results;

results = "";

links = xmlDoc.getElementsByTagName('link');

for (i = 0; i < links.length; i++) {

  results += links[i].getAttribute('href') + "\n";

}

Let me know if you have any questions.

Regards,

Pascal

[CarlesColl]

Also remember that RHINO javascript engine supports E4X and you can work with XML documents as "native" documents.

[sarathi]

Hi @pgrodowski  It throw error like "Cannot find function getElementsByTagName"

 This is My Code, I already moved xml file in system repository folder, The File Name is :url.xml

var params = {
path: "url.xml" /* STRING */
};

// result: XML
var Content = Things["SystemRepository"].LoadXML(params);
var links, results;

results = "";

links = Content.getElementsByTagName('link');

for (i = 0; i < links.length; i++) {

results += links[i].getAttribute('href') + "\n";

}
var result =results;

[CarlesColl · Accepted solution]

look for E4X I'm not sure the functions pointed out by Pascal before are there.