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How do I get the folder ID? Right now I am trying to use the Windchill REST Services site where it generates the request and response for you. I assume that under the data administration domain you can get folders from a container using /Containers{'ContainerID'}'/Folders but it seems like none of the folders show up when I provide the ContainerID for an organization. Windchill Version 12.1.2.0 and REST API 2.5
Hello @VH_10947268
Is there an issue with the input parameters?
ContainerID should be like OR:wt.inf.container.OrgContainer:123456789
It works on my server
Hi @Rocket_Max
The point is what he expects.
Your result is a folder in the Organization folder structure?
I guess that @VH_10947268 expects if he request for folders under organization he would get all folders from all sub containers as the libraries and products and that way I guess it does not work.
PetrH
Thanks for responses, @Rocket_Max @HelesicPetr
I’m not sure what a FolderID is exactly supposed to look like, but what I’m guessing is that if I have folders in a organization, I can provide the organization’s ContainerID and get all the folders’ IDs inside that organization. I’m not exactly sure what a Cabinet is, but maybe that is the FolderID? But I have multiple folders in that container and only one CabinetID shows up so I’m guessing not. Maybe I need to get folders as use the cabinetID as the container? I’m trying to figure out this because you can provide Folder@odata.bind in the API when creating documents, and I’m guessing it will create a document at that folder.
Hello,
I have same issue, The found folder is always the default folder under a Product (Context).
I cannot find the way to get the other folders ID.
I'm able to create one folder, its ID is not a cabinet
(i.e.: OR:wt.folder.Cabinet:789280659)
but a subfolder
(i.e.: OR:wt.folder.SubFolder:3178054303)
It looks that the get method /Containers('{ContainerId}')/Folders, Get Folder send back only Cabinet,
But I cannot find the way to get the subfolder ID
If you have an idea it will be great