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VB API - Line does not appear at correct place

TusharSuradkar
5-Regular Member

VB API - Line does not appear at correct place

When drawing a simple line using the sample VB API code, a line appears in the drawing but the wrong place consistently.

 

Using the code below, a line is expected from 0,0 to 20,0

 

Dim start As IpfcPoint3D
Dim finish As IpfcPoint3D

model = creoSession.CurrentModel


start = New CpfcPoint3D
start.Set(0, 0)
start.Set(1, 0)
start.Set(2, 0)

 

finish = New CpfcPoint3D
finish.Set(0, 20)
finish.Set(1, 20)
finish.Set(2, 0)

 

geom = (New CCpfcLineDescriptor).Create(start, finish)
lineInstructions = (New CCpfcDetailEntityInstructions).Create(geom, Nothing)
drawing.CreateDetailItem(lineInstructions)

 

When I check the coordinates again, they show correct values.

 

MessageBox.Show("Start = " & start.Item(0).ToString & " x " & start.Item(1).ToString & vbCrLf &
"End = " & finish.Item(0).ToString & " x " & finish.Item(1).ToString
)

 

TusharSuradkar_0-1666699974003.png

 

Am I missing any transformation?

 

1 ACCEPTED SOLUTION

Accepted Solutions
TusharS
4-Participant
(To:YaroslavSin)

Thank you for the reply @YaroslavSin and my sincere apologies for the delay.

The hint is helpful, but it will be immensely helpful if you could also point to how the online/offline help could be accessed and any code snippet for the transformation of screen coordinates to drawing coordinates.

I have tried this meanwhile:

 

' define line start and end point
Dim startPt As IpfcPoint3D
Dim endPt As IpfcPoint3D

startPt = New CpfcPoint3D
startPt.Set(0, 0)
startPt.Set(1, 0)
startPt.Set(2, 0)

endPt = New CpfcPoint3D
endPt.Set(0, 20)
endPt.Set(1, 20)
endPt.Set(2, 0)

Dim scrTrans As IpfcScreenTransform = (New CCpfcScreenTransform).Create(startPt, endPt, Nothing)

 

Can you please tell, with code, how to transform these points to drawing coordinates.

 

Thanks, in advance.

 

Best,

Tushar

 

View solution in original post

7 REPLIES 7

Did you find solution for this?

 

Regards,

Prasad

TusharSuradkar
5-Regular Member
(To:Prasad_G)

Not yet. Still waiting for a solution.

From the documentation:

The VB API methods and properties that manipulate drawings generally use screen coordinates.

 

You need to transform drawing coordinates to screen coordinates before to put it into a method.

TusharS
4-Participant
(To:YaroslavSin)

Thank you for the reply @YaroslavSin and my sincere apologies for the delay.

The hint is helpful, but it will be immensely helpful if you could also point to how the online/offline help could be accessed and any code snippet for the transformation of screen coordinates to drawing coordinates.

I have tried this meanwhile:

 

' define line start and end point
Dim startPt As IpfcPoint3D
Dim endPt As IpfcPoint3D

startPt = New CpfcPoint3D
startPt.Set(0, 0)
startPt.Set(1, 0)
startPt.Set(2, 0)

endPt = New CpfcPoint3D
endPt.Set(0, 20)
endPt.Set(1, 20)
endPt.Set(2, 0)

Dim scrTrans As IpfcScreenTransform = (New CCpfcScreenTransform).Create(startPt, endPt, Nothing)

 

Can you please tell, with code, how to transform these points to drawing coordinates.

 

Thanks, in advance.

 

Best,

Tushar

 

TusharS
4-Participant
(To:RandyJones)

Thanks @RandyJones 

I was using VB API as mentioned in the original post.

For that, I found a more relatable post here:

VB, Example code

 

The required lines are:

Dim currSheet As Integer = creoDrawing.CurrentSheetNumber
Dim sheetTransform As IpfcTransform3D = creoDrawing.GetSheetTransform(currSheet)
sheetTransform.Invert()
Dim startPtSheet As IpfcPoint3D = sheetTransform.TransformPoint(startPt)
Dim endPtSheet As IpfcPoint3D = sheetTransform.TransformPoint(endPt)

 

@Prasad_G - Please note 👆

RandyJones
19-Tanzanite
(To:TusharS)


@TusharS wrote:

Thanks @RandyJones 

I was using VB API as mentioned in the original post.

For that, I found a more relatable post here:

VB, Example code


Most of the time JLink, WebLink, and VB are very similar so seeing how to do any of them will help. In fact in this case it lead you to an VB specific article!

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