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Hello,
Has somebody an Idea, how to calculate the center of gravity (zs1) in zylindrical koordinates (The boundarys of the 3-Integrals are not really clear for me)?
See attached Files-sheet two of Kugelspeicher.mcdx.
Thank you very much!
Volker
Solved! Go to Solution.
Okay.
This is equivalent to your integral above except that the outer bound for radial integral is a function of height "rr(z).
Your integral has height as function of radius; I don't know how to write those functions.
I get CG's of odd shapes by integrating. Attached is integration in cylindrical coordinates.
Fred, I understand the integration of zylinders, etc.
But this is not the answer of my question.
I want to have the integration limits of the Integral concerning to the sketch:
This is a water-reservoir (shaded Area) of whitch i only want to know the integration limits for Integration to get the Volume.
Thank you
Sorry!
Mis-read the problem.
No Problem!
What is "s" in your formulas?
can you tell me the geometrical meaning of this?
It would be better for me to understand when you use the same parameter names whitch are given in the sketch.
Zylindrical koordinates:
Okay.
This is equivalent to your integral above except that the outer bound for radial integral is a function of height "rr(z).
Your integral has height as function of radius; I don't know how to write those functions.
Thanks, now we get closer to the problem.
Can you please post your MathCad file?
Is rr (z) equal to z (r)?- it confuses me.
Inner limits are d/2 and r (z), is that right?
You solved my problem.
I guess i had the wrong sequence in the integrals.
First "r" then "z" and at last "phi"
The equation:
I can't see the geometrical meaning, can you please explain in a sketch?
Solves for radius as a function of z, vertical position from the bottom of the sphere. (Pythagoras' Theorem.)
Height as a function of radius z(r) isn't helpful because there are two values of z for each r, while there is only one radius for each z.
The file is attached.
Valery,
sorry, but this doesn't solve my problem.
I wanted the correct limits for the Integration of a volume concerning to the upper shown sketch in my origin post.
Yes-It is necessary for finding the center of gravity
Thanks, anyway
Volker
Added
Z centers of gravity on page 2
Fred,
Thank you for your help.
I changed something in your File: I replaced rr(z) to r(z) because rr(z) is confusing me.
Volker