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Copper resistivity as a function of temperature

Cornel
19-Tanzanite

Copper resistivity as a function of temperature

Hi,

I am doing something wrong in Mathcad? Or maybe the reference plot is wrong?

Cornel_0-1735678666984.png

Cornel_4-1735678986955.png

 

Cornel_1-1735678688170.png

Cornel_2-1735678708455.png

 

Cornel_3-1735678723612.png

Prime 10

ACCEPTED SOLUTION

Accepted Solutions
ttokoro
20-Turquoise
(To:Cornel)

The reference plot is wrong. It plots 0.1*alpha*t

image.pngimage.png

View solution in original post

3 REPLIES 3
ttokoro
20-Turquoise
(To:Cornel)

The reference plot is wrong. It plots 0.1*alpha*t

image.pngimage.png

Cornel
19-Tanzanite
(To:ttokoro)

Ok.

@Werner_E 
In terms of units degree C or Kelvin, how is better to stick with for future calculation? Like  Cornel_3-1735721793700.pngor Cornel_4-1735721808344.png? I obtained with both the same result, but I find easier to understand writing in degrees C than converting degrees C to Kelvin and working further with Kelvin. 

 

Cornel_0-1735721586638.png

Cornel_2-1735721719630.png

Cornel_1-1735721647240.png

 

Werner_E
25-Diamond I
(To:Cornel)

Using temperatures can be tricky and usually you are best off using Kelvin throughout.

Your version1 works, but in general when you subtract temperatures you have to use Delta °C and not just °C.

Werner_E_0-1735728452869.png

But then you can't divide a temperature in degree not just by ! K or 1 °C or 1 Delta °C to get rid of the unit

Werner_E_1-1735728647073.png

To strip the unit you first have to subtract 0 °C and then divide by 1 Delta °C = 1 K (NOT by 1 °C).

Werner_E_6-1735729557011.png

 

Basically these conversions are the reason why your short and at first sight intuitively looking version works.

Your version works because, while

Werner_E_7-1735729703780.png

this also means that

Werner_E_8-1735729727831.png

and if you divide that by (1)K you get the necessary value.

 

Using the correct(??) Delta °C would make the expression more bloated.

You may strip the temp unit from the result of the subtraction

Werner_E_2-1735729180760.png
or just from the parameter T and subtract the simple scalar 20

Werner_E_4-1735729222859.png

If you really understand whats going on you sure can stay with something like your version 1

Werner_E_5-1735729261170.png

as its the shortest and the subtraction of 20 °C  looks correct at first sight to the innocent reader 😉

Of course you can always do like ttokoro  did and omit the temp units altogether 😉

 

According the plot difference I agree with ttokoro 

The author seems to have used 0.000393 instead of 0.00393 when creating the plot.

 

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