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Community Tip - Did you get an answer that solved your problem? Please mark it as an Accepted Solution so others with the same problem can find the answer easily. X

Display column vector

rrauck
2-Explorer

Display column vector

I defined a column vector as equal to the transpose of a 1 x 15 matrix (row vector). I verified that the column vector exists by displaying individual elements with a single subscript. I then take the transpose of this vector to get back to a row vector and it refuses to display when I type the vector name and enter =. I have verified that this works by using an example with fewer terms and it worked fine. What am I doing wrong?

ACCEPTED SOLUTION

Accepted Solutions
wayne
12-Amethyst
(To:rrauck)

Robert,

Would be advantageous for you to submit a file with your question.

Below is picture, does something help, if not, please send a file.

tmp.gif

View solution in original post

7 REPLIES 7
wayne
12-Amethyst
(To:rrauck)

Robert,

Would be advantageous for you to submit a file with your question.

Below is picture, does something help, if not, please send a file.

tmp.gif

rrauck
2-Explorer
(To:wayne)

You are right. I should have included a file. Here is one. I seem to have done the same things as you but mine does not work.

rrauck
2-Explorer
(To:rrauck)

It appears that my copy of Marhcad is damaged. Your example will not work on my machine.

wayne
12-Amethyst
(To:rrauck)

I did the same in your file, works fine, so you might be right. (used M15)

rrauck
2-Explorer
(To:wayne)

I reinstalled MathCad 15 and it now works as it should. The one difference I see is my row vector displays as a table rather than as a vector. Is that an optional setting or is it due to the length of the expression?

wayne
12-Amethyst
(To:rrauck)

For a specific result only, select the result

For the default for the file, select an area outside of a region

The on the menu bar: Format>Result>Display Options, change Matrix Style display

rrauck
2-Explorer
(To:wayne)

Thank you so much.

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