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How can I further simplify to display less cluttered output.
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No, that doesn't work, you'll get something like:
So:
I wouldn't know of a way to get the 1/3 before the matrix.
However in all cases you should realize that it is very hard to drive the results of the symbolic processor in any direction.
Success!
Luc
Try undefining a before the symbolic operation.
With a known to the symbolic processor, any symbolic operation will never result in an expression containing a itself, but use its definition instead.
Success!
Luc
No, that doesn't work, you'll get something like:
So:
I wouldn't know of a way to get the 1/3 before the matrix.
However in all cases you should realize that it is very hard to drive the results of the symbolic processor in any direction.
Success!
Luc