I graphed a line in the x y plane that begins at (-9,6) and stops at (2,4). This is because a college algebra book asked to consider the distance FROM P1 (-9,6) TO P2 (2,4). The authors then mention that the "midpoint formula is a bit more complex that it looks and is actualy a special case of a geometric theorem. Something about the ratios of the distances. Exploring this I then decided to use the mathcad software to create the two right triangles that would be associated with these three points. The point (answer) is P3 (-23/5,26/5). The reason I wanted to create these two right triangles is just to explore my ability to integrate the areas and compare the ratios. And I did it! My graph of the line that starts and stops at P1 and P2 is defined as f(x). To make the two triangles I wrote a program g(x) that uses inequalities and operators. In the placeholder for x and y however the g(x) is stated as g(a) and the x placeholder is x,a. I am not able to post a worksheet. But if anyone can visualize this Algebra problem and plot this scenario I would much appreciate it.
1 ACCEPTED SOLUTION
Accepted Solutions
Not sure what exactly you are trying to do, but it looks to me that you typed m(x) instead of m*(x) (or even better simply m*x)
Maybe the attached helps:
If you switch to 'advanced editor'
you will find and 'attach' link in the lower right corner.
You will also find that link if you edit your existing entry or answer (one of the options of the 'actions' link in the lower left corner).
You then can attach your worksheet.
(Oh, this forum is such a great place to be 
.)
Success!
Luc
Not sure what exactly you are trying to do, but it looks to me that you typed m(x) instead of m*(x) (or even better simply m*x)
Maybe the attached helps:
