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What I have understood so far is that you would like to vary the value of x. So you would have to turn any variable which depends on x into a function of x and use that in your solve block. Also the solve block has to be turned into a function of x like Results(x):= Find(...)
Then you can call results with different angles x or with a vector consisting of different angles.
There may be a problem because your solution vector consists of values with different units/dimensions. Wen can assign this to a vector consisting of three variables, as you had done, but we cannot assign it one variable or one function Results(x).
So we have to assign it a vector consisting of three function definitions. This is a bit inefficient, as the solve block now has to be called three times to get all three values for a single x and not just once. But the alternative is to temporarily strip the units and reattach them later and this would be the worse option, i guess.
WE
EDIT: See the answers here -> Re: Input Variables for the find function
