ACCEPTED SOLUTION
Accepted Solutions
Kok Kiang Lian wrote:
A sequence Ln is such that L1 = 0.2, L2 = 0.1 and
Ln = 2Ln-1 - 1.5Ln-2 ( n >= 3 )
Use Mathcad to determine the value of L43, giving your answer to 2 decimal places.
Need help to input this into Mathcad as i am new to this software... Thxs...
This is under which tutorial in Mathcad?
You will need to look for help about "range variables", plus basic expression entry and editing. Here's an example of how to create a similar sequence
Stuart
Kok Kiang Lian wrote:
A sequence Ln is such that L1 = 0.2, L2 = 0.1 and
Ln = 2Ln-1 - 1.5Ln-2 ( n >= 3 )
Use Mathcad to determine the value of L43, giving your answer to 2 decimal places.
Need help to input this into Mathcad as i am new to this software... Thxs...
This is under which tutorial in Mathcad?
You will need to look for help about "range variables", plus basic expression entry and editing. Here's an example of how to create a similar sequence
Stuart
Maybe you'd like zo create a function to get the n-th element of the series.
As you can see, the most obvious implementation (recursion) also is the most inefficient one.
