New triangle
Nov 09, 2019
01:26 AM
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Nov 09, 2019
01:26 AM
New triangle
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Algebra_Geometry
4 REPLIES 4
Nov 09, 2019
04:31 AM
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Nov 09, 2019
04:31 AM
Sneaky, Valery!
A complex modulus operator, as opposed to real square root operator, should sort it out.
Stuart
Jan 02, 2020
09:26 AM
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Jan 02, 2020
09:26 AM
Pythagoras theorem is valid when using component modulus only.
When using geometric rules it is absurd to take consideration of -1 mulltiplicant (i^2) /Avdo
Jan 03, 2020
07:55 PM
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Jan 03, 2020
07:55 PM
Jan 03, 2020
08:21 PM
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Jan 03, 2020
08:21 PM
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