ACCEPTED SOLUTION
Accepted Solutions
Of course in trhe actual sheet I would define those vectors in front of the solve block and also use a definition for the "Price" function which does not use predefined ranges:
@ValeryOchkov wrote:
Mathcad 15 in matrix form in attach
Why an error?
The sheet you posted does not throw any error!?
The effect which confuses you is due to the way Mathcad handles expression with ranges.
Sorry!
It was my error with indexes - hire are only 2 elements.
And I we cannot use indexes in Given-Find. I forgot about it!
See plrase my old message about it https://community.ptc.com/t5/PTC-Mathcad-Questions/Matrix-and-vector-in-Solver/m-p/20672
I was pretty sure that it would be you who would find the solution for this thread, but why not simply use vectors and matrices straightforeward? Seems the most easy way to do it to me.
BTW, if you don't like the hardcoded vector of 1's, you may replace it by funny expressions like seen in the following pic to make the solve block independent fron the matrix dimensions:
I forgot one of the easiest ways: diag(mp)*0+1
P.S.: I am not sure why the condition mp >= 0 has so much influence on the outcome (give it a try and delete it).
@ValeryOchkov wrote:
Thanks, Werner.
But we can have m=2 and p=3 for example - not square matrix mp.
I can't see any problems here:
Or, to be more generic, you can use one of the ideas given above:
BTW, I feel that the images you insert, are far too large. Images that large tend to destroy the readability of a thread.
Of course in trhe actual sheet I would define those vectors in front of the solve block and also use a definition for the "Price" function which does not use predefined ranges:
And how we can here have only one not 10 equation in Solver? (the Mathcad 15 sheet in attach)
Hoorray - catanary(?) again 😉
@ValeryOchkov wrote:
And how we can here have only one not 10 equation in Solver? (the Mathcad 15 sheet in attach)
Maybe simply by using an auxiliary function which calculates the vector of distances (squared).
I got rid of your mix of literal and vector subscripts and changed back the ORIGIN to 0.
