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ttokoro
21-Topaz I
Mar 20, 2020 9:53 AM UTC
Solved

Solve diagonal resistance of resistor 3D mesh.

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Diagonal resistance of regular polyhedron. R(4)=1/2, R(6)=5/6. How about R(8), R(12) and R(20)?

ttokoro
ttokoroAnswer
21-Topaz I
Mar 24, 2020 9:25 AM UTC

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t.t.

60 replies

24-Ruby IV
Mar 20, 2020 5:22 PM UTC

Cube.png

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21-Topaz II
Mar 22, 2020 3:13 PM UTC

Hi,

A simplification of the network topology allows you to easily apply Thevenin's theorem:

rete composta 2.jpg

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ttokoro
ttokoro21-Topaz IAuthorAnswer
21-Topaz I
Mar 24, 2020 9:25 AM UTC

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t.t.
ttokoro
ttokoro21-Topaz IAuthor
21-Topaz I
Sep 2, 2020 8:10 AM UTC

image.pngThe diagonal resistance of resistor 3D mesh is 5/6 ohm.

How about 1*2 3D Mesh?

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Each branch resister is 1 ohm. 

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t.t.
ttokoro
ttokoro21-Topaz IAuthor
21-Topaz I
Sep 8, 2020 8:14 AM UTC

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t.t.
ttokoro
ttokoro21-Topaz IAuthor
21-Topaz I
Sep 9, 2020 3:53 AM UTC

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i=2:    1*1*1

i=3:    1*1*2

i=4:    1*1*3....

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t.t.
ttokoro
ttokoro21-Topaz IAuthor
21-Topaz I
Jul 10, 2021 11:25 PM UTC

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t.t.
ttokoro
ttokoro21-Topaz IAuthor
21-Topaz I
Jul 31, 2021 12:54 PM UTC

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t.t.
18-Opal
Feb 21, 2022 1:51 AM UTC

I don't know why every body went to town on this. You already gave the V and I  so R = 5/6 ohms.

 

But as an academic exercise - as others have given but more colourful pictures are here:

 

https://www.rfcafe.com/miscellany/factoids/resistor-cube-equivalent-resistance-kirts-cogitations-256.htm

 

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ttokoro
ttokoro21-Topaz IAuthor
21-Topaz I
Feb 21, 2022 3:50 AM UTC

This is not solving 3D 1*1*1 grid resistor mesh only. Using Mathcad or other mathematical programs we can calculate more interesting resistor grid problems.

1/3+1/6+1/3 can not use if the grid is 1*1*2. I post many unique resistor grid problems here.  This time 60 node soccer ball resistor grid result is shown. Please try to solve it because I can not find any answer in WWW sites. Without using Math software, we can not solve such as R1-2 of resistor ball. 

 

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1*1*2                                                                                        1*1*1

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t.t.
18-Opal
Feb 21, 2022 11:15 AM UTC
21-Topaz II
Mar 15, 2023 3:57 PM UTC

What do you think of my solution?  Maybe I took the wrong node as a reference point?

2RBridges 0.jpg2RBridges 1.jpg2RBridges 2.jpg2RBridges 3.jpg2RBridges 4.jpg2RBridges 5.jpg2RBridges 6.jpg2RBridges 7.jpg2RBridges 5.jpg2RBridges 9.jpg2RBridges 10.jpg

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ttokoro
ttokoro21-Topaz IAuthor
21-Topaz I
Mar 15, 2023 11:35 PM UTC

I will check your circuit. Please upload your Mathcad worksheet. I use Prime 9 to solve it.

I view your post and I understand this is 3D cube circuit with 12 one ohms to find the equivalent resistance of diagonal nodes. Node method is used to solve the circuit. I think this is the best method to solve the resistance.

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t.t.
21-Topaz II
Mar 16, 2023 8:37 AM UTC

Hi,
Undoubtedly, I made some mistakes. As for the theory, I was inspired by some texts including: "Linesr and non linear circuits" by L. O. Chua, C. A. Desoer, E. S. Kuh, for the construction of the TABLEAU matrix. You can find my worksheet attached.
Greetings

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ttokoro
ttokoro21-Topaz IAuthor
21-Topaz I
Apr 19, 2025 3:54 AM UTC

3.4.5 ohms cube.

Pyta-345.jpeg

1 ohm circuit by 1 ohms. Each 1 ohm has different current when apply 1A for 1 and 13 nodes. 

1ohmby1ohms_3D.jpeg

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t.t.
ttokoro
ttokoro21-Topaz IAuthor
21-Topaz I
Dec 20, 2025 11:08 AM UTC

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Diagonal resistances of n-D cubes. AI only knows 3D and 4D ones. 

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t.t.
ttokoro
ttokoro21-Topaz IAuthor
21-Topaz I
Dec 25, 2025 6:43 AM UTC

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t.t.
ttokoro
ttokoro21-Topaz IAuthor
21-Topaz I
Jan 24, 2026 10:00 AM UTC

Source and Image Credits: Ellenberg, J., Libedinsky, N., Plaza, D., Simental, J., & Williamson, G. (2026). Bruhat intervals that are large hypercubes.

 

New hyper cube circuit 2026.

HyperCube20262.jpgHyperCube2026-2.jpg

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t.t.
ttokoro
ttokoro21-Topaz IAuthor
21-Topaz I
Jan 28, 2026 9:59 AM UTC

12-5x6.jpg

ttokoro_0-1769594411535.png

 

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t.t.
ttokoro
ttokoro21-Topaz IAuthor
21-Topaz I
Feb 21, 2026 12:01 AM UTC

Diagonal resistance of Galileo's 12-20 cube cauldron at the Milan Olympics.

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t.t.