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Mathcad 15M010. informs that there is a mistake in floating point or 10Е+307 is exceeded. The exponent has negative degree.
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jvm jjjvb wrote:
Thank you for the answer. I meant degree of exp.
It's the exponential argument I was referring to! See attached.
Alan
jvm jjjvb wrote:
The exponent has negative degree.
No, it doesn't for all values of k. The term exp(-p1.(t-k*Tp)) is greater than 10^307 when t = 0 and k = 255, for example, so that -p1.(t-kTp) = -7.156.10^6.(0 - 255.5.10^-5) = +9.124.10^4. Perhaps you mean the exponent to be the negative of the absolute value of p1(t-k.Tp)?
Alan
Thank you for the answer. I meant degree of exp. I changed degree of exp but still calculation doesn`t work.
jvm jjjvb wrote:
Thank you for the answer. I meant degree of exp.
It's the exponential argument I was referring to! See attached.
Alan
thank you. You helped me a lot.