cancel
Showing results for
Did you mean:
cancel
Showing results for
Did you mean:

Community Tip - New to the community? Learn how to post a question and get help from PTC and industry experts! X

17-Peridot

## Best Smoothing Approach

Hi

I am having issues formulation a smoothing function. Errors like "This value must be a vector of real numbers: pop up.

A working example will help a lot.

Prime 6 File Attached.

1 ACCEPTED SOLUTION

Accepted Solutions
17-Peridot
(To:Werner_E)

l having problems plotting.

12 REPLIES 12
24-Ruby V
(To:ppal)

Your approach failed because i is not a vector but a range!

In the pic below I used an undocumented trick to turn a range into a vector by adding a numeric evaluation when defining the variable i. Furthermore I chose the first value to be 1 instead of zero so the magnitude of i and r.dom match.

But of course you are on the save side if you define the necessary vector the "legal" way:

A working example can also be found in the help

You may also be interested in the information about smoothing in the MC15 help. Find it converted to pdf in the attachments.

16-Pearl
(To:Werner_E)

Is it possible to integrate the supsmooth function?

24-Ruby V
(To:DJF)

@DJF wrote:

Is it possible to integrate the supsmooth function?

supsmooth does not return a function but rather a vector of y-values corresponding to the vector of x-values provided.

You either can write your own "integration" function which works on datapoints given by vectors or you use interpolation (either linear or cubic splines) to turn the result of supsmooth into a function.

14-Alexandrite
(To:Werner_E)

A function for the supsmooth can be defined using the x and y vectors with interp function.  This new function can be integrated.

16-Pearl
(To:tietjee)

I see.  So, then no real advantage to using supsmooth over say a b-spline (unless you happen to like the fit better).  was hoping to save a step.  Thanks all.

17-Peridot
(To:Werner_E)

l having problems plotting.

23-Emerald III
(To:ppal)

What's the problem...it plots

doesn't it?

Luc

17-Peridot
(To:LucMeekes)

Sorry wasn’t clear. Can’t plot the smoothed  data.

24-Ruby V
(To:ppal)

I don't  see any attempt to plot r.smooth ??

Maybe you just have to move down the plot below the definition of r.smooth?

17-Peridot
(To:Werner_E)

Thanks!

24-Ruby V
(To:ppal)

It looks like you got confused by the indexing of vectors. By default Prime starts with zero.

You defined your range i starting from 1 and then plotted Loc[i over i. That way your plot gets shifted to the left for 1 unit - the first value of your data vector "Loc" is ignored and the second one (index 1) is assigned to 1, etc.

Correct plot should look that way:

17-Peridot
(To:Werner_E)

Thanks for spotting that.

Announcements