Community Tip - Have a PTC product question you need answered fast? Chances are someone has asked it before. Learn about the community search. X
I'm having trouble reconstructing an OFDM QAM signal using its amplitude and phase spectra obtained by using the DFT. The QAM signal is given in the image below.
I have tried to do it so far using the below equation.
This is the closest I have reconstructed it to the original. What am I missing?
I am using Mathcad 13.
You sure would get a better respones if you attach a worksheet. From the pic alone probably nobody would be able to determine what the problem ould be.
Would the following link be of any help?
http://www.comlab.hut.fi/users/tko/geta07/GETA fall 07- OFDM with MathCAD.ppt
No sorry that doesn't help. I was browsing through that just last night actually. I have attached my worksheet.
Jonathan Mayers wrote:
No sorry that doesn't help. I was browsing through that just last night actually. I have attached my worksheet.
Was just a try.
So hopefully someone with better technical background could jump in.
BTW,
1. Yes. The DC value is part of the reconstruction.
2. No. The last definition of X is what I'm supposed to use.
Jonathan Mayers wrote:
1. Yes. The DC value is part of the reconstruction.
2. No. The last definition of X is what I'm supposed to use.
OK, so I'm not of much help. It was just that I thought that
1) the DC value could be (is) negative!?
and I noticed that
2) you are using just the first 10 values of the 200 element vector X in the definition of sDFT for reconstruction. Obviously thats supposed to be done.
Yes because after the first K components, all others are zero and do not affect the calculation. The DC value is positive for me so I'm not sure what you mean. However, I changed the equation up a bit and instead I put my DC value to be negative and the two signals overlay exactly. For anyone who may be in a similar situation, find attached the mathcad 13 worksheet.
Ah yes, that makes sense, especially if you think of the reconstruction in its complex form
BTW, I think your DC should be X0/N (without the absolute value) or even better Re(X0)/N so you are prepared if cause of numeric errors you get an imaginary part in X0.