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Where is an error? Help please!
(One more same problem What is not correct in this optic problem?)
I know other simple solution this optic task (see please bellow), but I would like use this:
Simple solution - symbolic (by WolframAlpha.com site) and numeric (with nanotechnology help😞
Solved! Go to Solution.
Seems to work for negative values of x only.
Not sure and I had not tried (Prime is crashing all the time with your sheet) but maybe you run into the same problems with tan as I did in my solution above (y' gets infinte when x=0)
WE
What do you mean by this equation
and where does it stem from?
And why do you think that the argument of y´ should be a length (x(alpha)) while the argument of y is an angle?
If you write y´ here it has in any case to be the derivative with respect to alpha.
WE
Yes, Werner - not alpha but x - see please bellow
You may be able to keep alpha as the independend variable, but you can't use y'(x(apha)).
What you mean is
which Mathcad can't unserstand and you will have to replace it by
If you do so, other errors occur, though.
But I see you already rewrote your equations to accommodate for x as the independent variable, anyway.
WE
Thanks, but
Yes, I told you that you will run into other errors so it seems it was only the first mistrake in a row of others.
WE
From unnecessary ballast freed system but I don't understand what the error message would like to tell us!?
Looks like Mathcad does not like both derivaties to be in one equation.
Here we go.
It was necessary to introduce a dummy function and to redefine tan(). Not convincing, but at least it works.
Werner
I think you need to do it like the following Valery:
Note that the gradient is infinite at x = -F, which leads to difficulties for the integration routine. Hence the definition of the gradient function above.
Alan
Thanks, Alan and Werner.
The Prime 3 sheet in attach is without an error but has a false tan not sin in the last equation.
I feel the error but...
Seems to work for negative values of x only.
Not sure and I had not tried (Prime is crashing all the time with your sheet) but maybe you run into the same problems with tan as I did in my solution above (y' gets infinte when x=0)
WE
Do you know a surface with this Law of reflection:
Why are you trying this the hard way?
Numerically it is possible to solve this, but it can also be done symbolically:
Here is an animation
Note that the solution also works when F is negative, then the mirror is convex instead of concave.
Luc
Those embedded videos don't work (as so often).
Better simply attach the original avi-file.
-> Better qualitiy, more convenient to watch and more reliable
Here is what I see:
Werner Exinger написал(а):
Those embedded videos don't work (as so often).
We must load not avi but mov files. I do so and no problem!
And it is good to attach avi and mov files to the messege.
It should work with avi's, too. Having to convert animations to another format is an annoying additional step of operation.
But then, I never liked the embedded videos here in this forum for various reasons. Since the last forum design change it seems to have become worse.
Anyway, I played around with your last version and stumbled upon a quite strange effect.
**** DELETED *******
The real reason for the peculiar effect was sitting about 40 cm in front of the screen 😉
Werner
OK, here is really a strange effect.
Why does this small change of the end value has such a big impact on the overall shape of the solution??
I could understand if the algorithm goes havoc near x=0, but not at the start at x=-F.
Or is it working from x.end back to the start? Don't think so as it has to use the initial conditions for x=-F first, I guess.
Werner
A lens not mirror - but two video - from avi and mov files
Luc,
Your animation is not visible for the viewing. Please attach to the message the archive of this animation.
VladimirN. написал(а):
Luc,
Your animation is not visible for the viewing. Please attach to the message the archive of this animation.
See please:
I noticed it wasn't visible. I even got to see my animation attachment efforts as separate items in the topics list:
but with NO access allowed. When I try to select one, Iget:
Here's a zip file with the AVi's.
Enjoy!
Luc
Dear Luc, did you do this analysis in Mathcad 11 or Mathcad 15? If in MC11 would this work in 15 seen the different symbolic engine? Happy New Year and thanks for the many very instructive worksheets over the last years.
LucMeekes написал(а):
Numerically it is possible to solve this, but it can also be done symbolically:
Symbolically it is possible to solve this, but it can also be done numerically:
LucMeekes написал(а):
Why are you trying this the hard way?
I would like to solve this problem!
Do you know material of this mirror surface?
How can we use the try (on error - Mathcad 15) operator: