Hello Friends,
I want to know the solution of the given below equation using Mathcad Prime 3.1.
In above equation, two variable i.e. Phi. & Zeta is given but need to find out Psi.
There is a figure given for reference which tells the relation in these variable as attache herein post.
Can anyone tell me how to calculate Psi using the given references and also if I need to plot it, then how can it be achived.
Thanks, Yogesh
Glad you are up and running.
The function Ft is defined in a strange way with those return statements as factors and obviously does not yield the correct results for n>1 (always 0).
You may consider replacing it with something like this:
Hi Friends,
I did not notice it earlier but the plot we have done using your methods is somewhat a bit different than my original snap (as per IEC).
Addtionally, I'd be interested to know that when we use logspace function for zeta then only these lines are plotted else only points. So what is other way to achieve the same thing because when I use the zeta variable down the plot it converts into the matrices.
Thanks for your help.
As already said in my other answer using the quickplot results in a curve which is edgy in the range of the smaller zeta values.
You could provide a range for zeta instead of the vector cretaed by logspace:
The problem is that we have much too much values where zeta is higher and maybe too few values (steps too large) where zeta is smaller.
Change the 0.2 to 0.5 to see that this is a too large step in the smaller zeta range and makes an edgy curve
Change the 0.2 to 0.15 to see how long its takes to draw the curves
Change the 0.2 to 0.11 to see a strange effect
Furthermore this method would not be useful if the lower limit is not 10^-1 but 10^-6.
As we have the abscissa logarithmic scaled we would like to have the exponents evenly spaced, not the values itself. This is exactly what logspace does we can simulate it with a range variable:
The plots look the same for me.
The plot you try to duplicate starts at 10^-1 but yours starts at 10^-6. Thats the reason the plots look different
You can do the plot without the logspace vector using Primes quickplot feature (use an undefined variable on the abscissa and set the desired range at the axis itself). But if you do so, Prime seems to chose automatically equidistant values for zeta and so you don't get a smooth curve for the smaller values of zeta. You would not need vectorization if you use quickplot, but I was to lazy to change that in the plot;-)
If you need zeta to be a single scalar you may redefine it after the plot or, even better, use a different variable for plotting. Keep in mind that when you use a function the argument must NOT be the same name than the one you used when you defined the function (formal argument vs. actual argument).
Here is what you are probably looking for.
Sheet in format Prime 5 attached
BTW, to embed pictures in the text you have to use the "Photos" button at the top toolbar. If you just copy and paste a picture (which we all think is a feature which should be available, alas it isn't) it looks OK for you in first place but only until you press the "Post" button. Thats sure an undesired and irritating behaviour.
Hi,
In your sheet the definition of function f is wrong in the second term
This is why it will not solve
Cheers Terry
