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Hi,
I want to write a code where for some vector [25 15 23 20 .. n ] i want to find if the ratios of the adjacent values exceed 1.2 of each other. The output result would be like "Yes" or "No". how do i go about doing that?
For example: for vector [15 25 20], because 25/15>1.2, I want the answer as "Yes".
But I would also want the same answer "Yes" if it was [25 15 20] because in this case also for the adjacent values 25/15>1.2.
Thanks.
Edit1: added "ratios of the"
Edit2: added example
Solved! Go to Solution.
Maybe a custom command like the following will do the job:
In case you are using Prime, use "else" instead of "otherwise".
I'm so sorry that i mistyped the question.
For example: for vector [15 25 20], because 25/15>1.2, I want the answer as "Yes".
But I would also want the same answer "Yes" if it was [25 15 20] because in this case also for the adjacent values 25/15>1.2.
Thanks for your reply
OK, so its the Ratio, not the difference.
And what do you expect as a result? Just one single "Yes" or "No" for the whole Vector if the Ratio of any adjacent pair exceeds 1.2, or a "Yes" or "No" for every triple (or pair?) in the Vector?
If the latter - what about the ends? Do you expect an n x 1 vector, an (n-1) x 1 vector or an (n-2) x 1 vector as a result?
Here is a variant which returns just a single answer:
Just one single "Yes" if the Ratio of all adjacent pair does not exceeds 1.2, and just a single "No" if the Ratio of any adjacent pair does not exceeds 1.2.
Sorry for my bad english.
Thank you.
OK, so you would have to exchange "Yes" and "No" in my last attempt.
Otherwise it should do what you demand.
Thanks I was looking for the algorithm on how i should work it out;; your last attempt helped me a bunch!! thanks a lot!