trying to understand PDE
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trying to understand PDE
Hi,
I am trying to learn PDE in mathcad,.. Its my first time with PDE, could anyone pls help me with this?
Thanks in advance
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Calculus_Derivatives
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Its unclear to me what you are trying to do.
q is treated as the spatial variable name first, but when it comes to the BC you treat it like a functon!?
n(q,t) is neither defined nor searched for.
u is first defined as a function in 1 variable and then used as if its a function in two variables.
Concerning the syntax of the Pdesolve() call Alan pointed you in a previous thread to the appropriate help page. Please read and use the information given there and study the examples and the quicksheet.
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this became a bit confusive, when i used u many times.
well this is what i want to define actually du/dt (q,t) = -n (q,t)*v (q,t)
what do u mean by BC?
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preeti baskaran wrote:
this became a bit confusive, when i used u many times.
well this is what i want to define actually du/dt (q,t) = -n (q,t)*v (q,t)
And what do you know about n and v? You are just searching for u?
what do u mean by BC?
Boundary condition.
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And what do you know about n and v? You are just searching for u?
n and v are just two varibles which are initiliased and they should act according to two contraints that is q = quality and t = time.
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preeti baskaran wrote:
And what do you know about n and v? You are just searching for u?
n and v are just two varibles which are initiliased and they should act according to two contraints that is q = quality and t = time.
So n and v are NOT variables but (undefined) functions!?
Looks to me like you are trying to solve a *system* of equations, aren't you?
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So n and v are NOT variables but (undefined) functions!?
ok, now I am confused between the terms.
it can be interpreted as the the rate of change of -n and q with respect to q and t. defining them as functions is to set the initial contions in mathcad, isnt it?
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preeti baskaran wrote:
So n and v are NOT variables but (undefined) functions!?
ok, now I am confused between the terms.
it can be interpreted as the the rate of change of -n and q with respect to q and t. defining them as functions is to set the initial contions in mathcad, isnt it?
No, but if n and v should change dependent on q and t, they are functions in those two variables.
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It looks to me like you have an ode system, not a pde. Look at odesolve.
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The attached file contains some comments and questions aimed at pointing you in the right direction (I hope!).
Alan
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thanks! I will look on it