New triangle

[ValeryOchkov]

[StuartBruff]

Sneaky, Valery!

A complex modulus operator, as opposed to real square root operator, should sort it out.

Stuart

[ptc-5737066]

Pythagoras theorem is valid when using component modulus only.

When using geometric rules it is absurd to take consideration of -1 mulltiplicant (i^2) /Avdo

[ttokoro]

[ttokoro]