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1-Visitor
December 20, 2018
Solved

Theoretical Flow Rate calculation

  • December 20, 2018
  • 1 reply
  • 3946 views

I am in school and trying to work through this example in the book. It all works out except the Theoretical Flow Rate which the book specifies as 15.3 GPM. From a little research I believe the issue is with how MathCad defines rpm but I can not figure it out. Capture.JPG

Any help would be greatly appreciated,

Frank 

Best answer by DJF

Don't divide by 231 - Mathcad knows units so it's going to do that on it's own, you're forcing it to do it twice.

Also, you have a unit of revolution in your input but none in your output.  So, Mathcad is going to divide by 2*pi to get rid of it.  Dealing with anything rpm related can be tricky.    

  

So without the 231 and 2*pi factors you get the expected answer.

1 reply

DJF16-PearlAnswer
16-Pearl
December 20, 2018

Don't divide by 231 - Mathcad knows units so it's going to do that on it's own, you're forcing it to do it twice.

Also, you have a unit of revolution in your input but none in your output.  So, Mathcad is going to divide by 2*pi to get rid of it.  Dealing with anything rpm related can be tricky.    

  

So without the 231 and 2*pi factors you get the expected answer.

1-Visitor
December 21, 2018

I greatly appreciate your answer. I was able to exchange the 231 with 2*pi and get the correct answer. I researched and now understand the 231 portion because that is converting in^3 to gallons which Mathcad does through its unit conversion but I must admit I still do not quite understand the rpm (2*pi)portion. Thanks again for the assistance!

23-Emerald I
December 21, 2018

@FrankMozingo wrote:

 I still do not quite understand the rpm (2*pi)portion. Thanks again for the assistance!


rpm should be considered "revolutions per minute", there are 2 pi radians per revolution, so you needed to correct for that

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