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Best answer by Werner_E

Looks like homework, doesn't it?

Where are your attempts in MC15?

What have you already tried?

 

BTW, the condition f(x)>= sine is somewhat strange.
First task should be to make a plot (either by hand or via Mathcad) which shows that you are just looking for the minimum of the part of the curve plotted thick red. Fortunately this minimum (green dot) can be found easily using the zero of the first derivative ...

Werner_E_0-1715567331610.png

 

The name "arctg" is quite outdated and should no longer be used according to the current standard (ISO 80000-2)

 

Werner_E_1-1715566869933.png

In Mathcad this function is called "atan".

 

2 replies

Werner_E25-Diamond IAnswer
25-Diamond I
May 13, 2024

Looks like homework, doesn't it?

Where are your attempts in MC15?

What have you already tried?

 

BTW, the condition f(x)>= sine is somewhat strange.
First task should be to make a plot (either by hand or via Mathcad) which shows that you are just looking for the minimum of the part of the curve plotted thick red. Fortunately this minimum (green dot) can be found easily using the zero of the first derivative ...

Werner_E_0-1715567331610.png

 

The name "arctg" is quite outdated and should no longer be used according to the current standard (ISO 80000-2)

 

Werner_E_1-1715566869933.png

In Mathcad this function is called "atan".

 

6-Contributor
May 22, 2024

And how do you find the solution of it?

25-Diamond I
May 24, 2024

@TT_11056782 wrote:

Thank you!

and how does the constraint affects the function here?


Which constraint?

And what do you mean by "here"? My approach using "root" or the program I posted, base on your attempt?

 

Bit ignore the constraint that f(x) should be larger than the sine function given because in the plot it can be seen that this constraint is fulfilled anyway.

My root-approach looks for a solution in the range pi to 2 pi.

The program based on your attempt start with a guess value of pi and so also finds the desired solution.

Community Moderator
May 16, 2024

Hello @TT_11056782

 

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