Why L1^2 is missing?

Forum|Forum|3 years ago
March 28, 2023
2 replies
1821 views

Hello everyone!
I have been looking into the transient in this passive circuit for some time. However, I see that the theoretical results do not coincide with those using the TABLEAU matrix. As you can see at the end of the worksheet, the denominators are slightly different i.e. L1^2 is missing. Why. Whoever finds the source of the problem is really good.
Thanks to anyone who can answer.
Greetings. Why L12 is missing.....jpg

1_R1L1R2L2-transient-study.zip

Best answer by ttokoro

L

LucMeekes

23-Emerald IV

Buongiorno,

I think you are not missing an L1^2*s^2 term where you indicate it, on Vb2(s) side, but you have one too many on the other side , for V.1(s).

Here's my quick analysis of the circuit:

Success!

Luc

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-MFra-

Author

21-Topaz II

Thanks, but the following solution seems more correct to me: L. M. answer.jpg

L

LucMeekes

23-Emerald IV

I think that ( whether I assume that Vcc, like V2 and V3, is a function of s, or you state that Vcc is a constant, so its Laplace transform is Vcc/s ) may be a matter of taste.

But we (now) both agree that there should be no L.1^2 term in the denominator. Hence Vb2(s) is not missing a term, but V.1(s) has one too many.

Success!
Luc