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IRarch1-Visitor
1-Visitor
January 30, 2018
Solved

Matrix within a Matrix

  • January 30, 2018
  • 1 reply
  • 1774 views

Hello everyone,

 

I have the following matrices:

 

x = (15 -17)    y = (-6 20)   z = (55 -75) 

 

I would like to combine them to form a new matrix such as,

 

A = (x y z)

 

I'm thinking (not sure if its right) A would turn up to be a 1x6 matrix.

 

A = (15 -17 -6 20 55 -75)

 

Then I would like to get the maximum absolute value of A which if everything is possible up to this point then the result would be 75.

 

Any suggestions?

 

Thanks!  

Best answer by LucMeekes

Use

A:=augment (x,y,z).

Then the Minimum of your matrix A will be found with:

MinA:=min (A) = -75

To find the Maximum absolute value use:
MaxAbsA:=max (abs (A))= 75

 

Some more:

LM_20180130_MatrixInMatrix.png


Success!
Luc

1 reply

L
LucMeekes23-Emerald IVAnswer
23-Emerald IV
January 30, 2018

Use

A:=augment (x,y,z).

Then the Minimum of your matrix A will be found with:

MinA:=min (A) = -75

To find the Maximum absolute value use:
MaxAbsA:=max (abs (A))= 75

 

Some more:

LM_20180130_MatrixInMatrix.png


Success!
Luc

    A
    asmamanawar1-Visitor
    1-Visitor
    March 31, 2018

    Yes, Your solution is correct. This is the simple way to get the solution of this problem. Same solution also in my mind but you already did good effort.

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