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rstavish1-Visitor
1-Visitor
October 10, 2014
Question

Another vault question

  • October 10, 2014
  • 3 replies
  • 1491 views
Windchill Admins,

I have another question relating to vaults. If I have a an object in Windchill and it has several iterations and revisions. Would each of those iterations and revisions have a unique file in the Vault? So if the iteration history show 8 then there would be 8 corresponding files in the Vault?

Thanks
Rich

Richard Stavish
Pro/E System Administrator

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3 replies

B
BenPerry15-Moonstone
15-Moonstone
October 10, 2014
Yes.

And this is where they are located, if you can run a query against the database:

select
mas.cadname cadname,
doc.VERSIONIDA2VERSIONINFO || NVL2(doc.oneOffVersionIdA2oneOffVersi ,'-' || doc.oneOffVersionIdA2oneOffVersi,'') || '.' || doc.ITERATIONIDA2ITERATIONINFO ver,
ad.modifystampa2 modified,
ad.role role,
M.path,
to_char(fi.uniquesequencenumber,'0000000000000x') vault_filename,
ad.filename,
m.status,
ad.filesize filesize_bytes
from
holdertocontent hc,
applicationdata ad,
fvitem fi,
EPMDocument doc,
EPMDocumentmaster mas,
FVMOUNT M
where
hc.ida3b5 = ad.ida2a2
and ad.ida3a5 = fi.ida2a2
and hc.ida3a5=doc.ida2a2
AND Fi.ida3a4= m.ida3a5
--and ad.role='PRIMARY'
and doc.ida3masterreference=mas.ida2a2
and mas.cadname like 'lowercasefilename.prt'
order by
mas.cadname,
ver,
role

D
ddemay1-Visitor
1-Visitor
October 10, 2014
No. If just database stored content was updated a new iteration can potentially point to a previous iteration or revision of content. A new file has to be transmitted to the server. This doesn't imply at a binary level of 1's and 0's that the two files are identical but to you they may look identical. A good example is updating properties inside a CAD file, but not altering the model.



D
dgraham-41-Visitor
1-Visitor
October 10, 2014

Guys,

I think the easiest way to look at this is too ask did I upload a file during the creation of my new iteration. If no, than the new iteration points to the same file as the previous iteration. Simple as that.

David Graham
Windchill Developer

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