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1-Visitor
April 30, 2015
Question

Intercept of Two Equations: y^2.5=1-x^1.5 and y=(a/b)*x

  • April 30, 2015
  • 5 replies
  • 4365 views

Hello,

I have 2 equations and I have to find the intercept. The equations are:

y^2.5=1-x^1.5

y=(Rs/Rt)*x

In this equation Rs and Rt are constants and we need the solutions that will make x and y to be in between 0 and 1.

I have been trying but I get a warning message that I dont understand. Attach is a picture of what my code looks like. Any help will be appreciated.

5 replies

19-Tanzanite
April 30, 2015

Since the picture doesn't show the error message, it would be helpful if you told us what it is. Even better, post the worksheet (in the edit dialog, click on "Use advanced editor" at the top right).

19-Tanzanite
May 1, 2015

Why not just use a numerical solution

intercept.PNG

Alan

1-Visitor
May 1, 2015

Hello,

I need the euqations because I need to develop an equation.... If use values then I am not going to be able to develop the equation. here is a code. Any help will be appreciated!

19-Tanzanite
May 1, 2015

Why do you need the equation? Like lturek, I don't think you will find a closed form solution. I also tried the Maple symbolic engine used in earlier versions of Mathcad, and it does not give anything useful either.

1-Visitor
May 1, 2015

At the end you demand Mathcad to solve an equation like R*u^5+u^3-1=0 symbolically, which it can't do - like many other math packages, including On-line Wolfram Alpha. (u=x^0.5 and R=ratio^2.5).

I don't think that you will be able to get a closed solution to this equation.

There is no closed formula to solve an algebraic equation of fifth order.

But as Alan pointed out Mathcad can provide a numerical solution for any given ratio.

And you will get a pair (x,y) where both are in the range (0,1) for any positive ratio Rs/Rt.

I am not sure what you would need a closed expression for, but I guess the best you will be able to achieve is the creation of a lookup table for the values of x with respect to the value of the Ratio Rs/Rt which can be used by another (embedded?) program to provide the values.

ratio.jpg

1-Visitor
May 1, 2015

Hello,

We are trying to prove or disprove and provide an equation.

According to several sources the ratio from OB/OA=1/sqrt(y^2.5+x^1.5)

in the chart you see 2 examples: Example 1 and Example 2

The ratio is been calculated based on the distances for example:

OA=sqrt(x^2+y^2)

OB=sqrt (x^2+y^2)

But we need to get what will be x and y for point B....

we know the equations for the 2 curves and that they intersecpt....

y=(Rs/Rt)x

y^2.5+x^1.5=1

x and y will always be <=1

Looks to me that the ratio provided is wrong....

OB/OA=1/sqrt(Y^2.5+x^1.5).... WRONG!!!!!

So I am trying to provide a real equation....


19-Tanzanite
May 1, 2015

It's not clear to me what defines the distance OA. The distance OB is the distance from the origin to the intersection of the curves y=(Rs/Rt)*x and y^2.5+x^1.5=1, but what is OA?

1-Visitor
May 1, 2015

A is the actual point... is where we actually are... we are looking for a equation that will define the ratio betwwen the allowable to the actual...

the y^2.5+x^1.5=1 define the limit... the allowable.... thats why point B is there... it extend from A hope this make sense


19-Tanzanite
May 1, 2015

I do not believe there is any closed form expression for the ratio OA/OB.

Do you actually need such an expression, or just a proof that the expression you have been given is wrong?

1-Visitor
May 4, 2015

Today I know that equation is wrong... Looks to me that is been used as an approximation. I am planning on doing it graphically.. and see if I find a pattern that will help find simplify my equation. Yep I agree there is no way this equation can be easily solve the way it is.

You guys are awesome!!!