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15 replies

terryhendicott
21-Topaz II
Oct 12, 2025 6:42 AM UTC

Hi Fred,

I had some fun.

Have my answer in a closed area also to stop the honest among us who don't peek.

Cheers

Terry

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ttokoro
21-Topaz I
Oct 12, 2025 7:51 AM UTC

image.png

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t.t.
terryhendicott
21-Topaz II
Oct 12, 2025 9:29 AM UTC

Hi Fred,

Remember this is fun.

Intersection of perpendicular bisectors of AB and BD meet at the center.  Once have center can get radius center to A.

Capture.JPG  

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Werner_E
25-Diamond I
Oct 12, 2025 1:50 PM UTC

As you posted a file in Prime Express 4.0 format, I thought I would provide an Express solution as well.
Basically simply two perpendicular bisectors are intersected to get the center M of the circle and the radius is the distance of M to one of the three circle points A, B or D.

Werner_E_0-1760276930700.png

Prime Express 4 file attached

 

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Werner_E
25-Diamond I
Oct 12, 2025 3:17 PM UTC

Here a more basic approach without analytical geometry, just using good old Pythagoras.

The solving of a system of equations (in r and MF) is somewhat hidden by  first expressing MF with r and putting that expression in the second equation.

Werner_E_2-1760283108961.png

"root" function can be avoided by some manual term manipulations

Werner_E_3-1760283230867.png

Prime Express 4 file attached

 

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18-Opal
Oct 12, 2025 9:06 PM UTC

Since this was for fun I thought I'd see if I could replace Mathcad with Gemini Ai.

I have a circle. I draw a chord AB =45cm. Then I draw a line at 90 degrees to AB =20cm. This line is inside the circle. I draw another line perpendicular to  AC towards the circumference. This line is CD =15cm and terminates on the circumference of the circle. Determine the radius.

ppal_6-1760303132747.png

 

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23-Emerald V
Oct 12, 2025 11:20 PM UTC

I was going to go Werner's "good old Pythagoras" route until I saw he'd already posted it.   So, as we've had Greeks, I'll go Indian instead.

 

2025 13 09 A.png

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18-Opal
Oct 12, 2025 11:28 PM UTC

Well they are both Indian.

The Baudhayana Shulba Sutra, an Indian text written between the 8th and 5th century BC, contains a statement of the theorem, a specific case for the isosceles right triangle, and the general case. This predates Pythagoras by about 300 years. 

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19-Tanzanite
Oct 15, 2025 12:25 PM UTC

Here's another approach (Prime 11 Express):

JUstForFun.png

 

Alan

 

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Werner_E
25-Diamond I
Oct 15, 2025 1:41 PM UTC

It's nice to see so many ways to skin this cat!

 

> (There is probably a name for this relationship, but, if so, I've long forgotten it!)

 

In German it's called "Höhensatz". According to Wikipedia its called "Geometric Mean Theorem" in English -> Geometric mean theorem - Wikipedia

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