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3-Newcomer
September 6, 2025
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No solution was found

  • September 6, 2025
  • 1 reply
  • 639 views

Hi,

Can anybody solve equation ? Solution is x =1, but Mathcad doesn't see this solution ...

 

AB_14100650_0-1757187598967.png

 

Best answer by Werner_E

Given that

Werner_E_0-1757188857299.png

x=0 can be considered a solution as well.
Formally, f(x) is not defined at x=0, but can be continuously extended.

 

Additionally there are a lot of non-real solutions as well.

 

And while Prime's symbolic engine can't find a solution, Prime's numeric "root" function does. A solve block with "find" sure would do a similar job, but is more cumbersome and ugly looking.

 

You can use the "root" function by providing a guess value

Werner_E_1-1757189478088.png

non-real guesses may lead to non-real solutions

Werner_E_2-1757189802200.png

 

or you can use the "root" function by providing an interval (only for real-valued solutions).

Werner_E_3-1757189869294.png

 

You may also take the logarithm on both sides of the equation

Werner_E_4-1757190028599.png

and so look for the roots of the derived function g(x). Here the symbolics finds both solutions and I must confess that I am surprised that the "assume" modifier really does its job as intended because normally its ignored in such situations.

The modifier "fully" is supposed to return all solutions in one go, but unfortunately has no effect here.

Werner_E_5-1757190704716.png

 

Prime 11 sheet attached

1 reply

Werner_E25-Diamond IAnswer
25-Diamond I
September 6, 2025

Given that

Werner_E_0-1757188857299.png

x=0 can be considered a solution as well.
Formally, f(x) is not defined at x=0, but can be continuously extended.

 

Additionally there are a lot of non-real solutions as well.

 

And while Prime's symbolic engine can't find a solution, Prime's numeric "root" function does. A solve block with "find" sure would do a similar job, but is more cumbersome and ugly looking.

 

You can use the "root" function by providing a guess value

Werner_E_1-1757189478088.png

non-real guesses may lead to non-real solutions

Werner_E_2-1757189802200.png

 

or you can use the "root" function by providing an interval (only for real-valued solutions).

Werner_E_3-1757189869294.png

 

You may also take the logarithm on both sides of the equation

Werner_E_4-1757190028599.png

and so look for the roots of the derived function g(x). Here the symbolics finds both solutions and I must confess that I am surprised that the "assume" modifier really does its job as intended because normally its ignored in such situations.

The modifier "fully" is supposed to return all solutions in one go, but unfortunately has no effect here.

Werner_E_5-1757190704716.png

 

Prime 11 sheet attached

3-Newcomer
September 6, 2025
Tkanks 🙂