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7-Bedrock
December 26, 2022
Solved

Square root units question

  • December 26, 2022
  • 2 replies
  • 2221 views

I have to identical equations using a square root (flow calculation).  If I use the "psf" units for lbm/ft^2, the radical doesn't evaluate the squared units correctly.  But if I force the units to be lbm/ft^2 under the radical, then the expression evaluates correctly to lb/s; mass flow.  

 

I don't understand why this doesn't evaluate correctly.  Is there a way to make this more robust?

 

See attached.

Best answer by Werner_E

Why do you think that psf = lbm*ft^-2 ??

There is a gravity factor missing:

Werner_E_0-1672034056530.png

So you possibly are looking for

Werner_E_1-1672034076359.png

 

 

2 replies

Werner_E25-Diamond IAnswer
25-Diamond I
December 26, 2022

Why do you think that psf = lbm*ft^-2 ??

There is a gravity factor missing:

Werner_E_0-1672034056530.png

So you possibly are looking for

Werner_E_1-1672034076359.png

 

 

gshockxcc7-BedrockAuthor
7-Bedrock
December 26, 2022

Yes, you're correct.  Oversight on my part.  Thanks for catching that mistake.

23-Emerald I
December 26, 2022

In your second line you change psf into lbm/ft^2.  This introduces a (happy in this case) unit balance error.

 

Mathcad recognizes pounds force (lbf), pounds mass (lb or lbm).  When you edited the units you (happily) removed an extraneous gravity acceleration from your first line.  Since Mathcad recognizes and converts units, There's  a better way:

Fred_Kohlhepp_0-1672064248883.png

Note that you have squared the 0.915 as well as the unit ft  when specifying area.

File attached Prime 8

 

gshockxcc7-BedrockAuthor
7-Bedrock
December 26, 2022

Yes, thank you.  I left off the other constants for the area, so I was only squaring diameter, but I take your point.