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ngothankar1-Visitor
1-Visitor
October 12, 2015
Solved

How to get location of the dimension in the drawing

  • October 12, 2015
  • 7 replies
  • 3476 views

Hi,

I am trying to get model's dimension location in drawing.

I am using ProDimensionLocationGet () and ProDimlocationTextGet() APIs but the location I am getting I am not able to match wrt to drawing coordinate.

do we need to process the point3d position again in order to conver it in drawing CSYS?i

Thanks in advance

Nikhil


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Best answer by mender

177,126 is in world coordinates, to judge by the picture.  You can transform that into drawing units with the trf matrix from ProDrawingSheetTrfGet.

7 replies

FrédéricPradier1-Visitor
1-Visitor
October 13, 2015

Can you draw a simple example of your expected result please?

MarkStallard1-Visitor
1-Visitor
October 13, 2015

Nikhil -

I haven't yet used ProDimensionLocationGet or ProDimlocationTextGet, but I'll see if I can help just the same.


the location I am getting I am not able to match wrt to drawing coordinate.


What kind of coordinates are you getting?  Are they even close?


The documentation for ProDimlocationTextGet states that it returns the location in "model coordinates". That should be the coordinates of your drawing. If the coordinates are wrong, but close, try changing the value of ProDimlocationTextGet's has_elbow argument.

If the coordinates make no sense to you at all, I suggest that you open a support call with PTC.

Good luck with this.

|+|  M a r k  |+|


Ketan_Lalcheta2-Explorer
2-Explorer
October 14, 2015

Hello Nikhil,

Try ProDrawingDimensionPosGet API.

Regards

Ketan

ngothankar1-VisitorAuthor
1-Visitor
October 14, 2015

Hi,

I have created a 100x100x100 mm solid part and paced it on C size drawing sheet with 1 vertex at 0,0 position.

here the coordinate of a point placed on dimension 100 on vertical edge (behind X).

Now how to justify 177,126 as location of dim 100?

Both ProDrawingDimensionPosGet() &  ProDimlocationTextGet(), returning same value of point3d.

Thanks

Nikhil

mender12-AmethystAnswer
12-Amethyst
October 14, 2015

177,126 is in world coordinates, to judge by the picture.  You can transform that into drawing units with the trf matrix from ProDrawingSheetTrfGet.

ngothankar1-VisitorAuthor
1-Visitor
October 15, 2015

Hi,

Thanks every one for your effort and suggestions.

toolkit APIs return screen coordinate information, we need to transform it in to drawing sheet coordinate.

use ProDimlocationTextGet to get location of dimension coordinate and use following method can be used to achieve this.

void UserScreenToDwg (ProDrawing drawing,ProPoint3d scn_point,ProPoint3d drw_point) {

  ProName    w_size;

ProMatrix  matrix;

int cur_sheet;

ProError err;

err = ProDrawingCurrentSheetGet(drawing, &cur_sheet);

err = ProDrawingSheetTrfGet(drawing, cur_sheet, w_size, matrix);

err = ProPntTrfEval(scn_point, matrix, drw_point);

}

MarkStallard1-Visitor
1-Visitor
October 15, 2015

Nikhil -

I'm glad you were able to resolve this problem. If your solution is the correct one, then please report to PTC that the documentation for ProDimlocationTextGet is incorrect.  Here's how it describes the output parameter pnt on Creo Parametric 3.0 M050:

The location, in model coordinates, of the dimension text (if has_elbow is PRO_B_FALSE) or the elbow joint (if has_elbow is PRO_B_TRUE). Pass NULL when not required.

Given your findings, the above sentence should read "The location, in screen coordinates ..."

|+|  M a r k  |+|

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