Swept Blend

Forum|Forum|9 years ago
July 13, 2016
3 replies
4487 views

Hello I am trying to use the swept blend feature to blend a hexagon shape to a square, I have increased the blend vertex of the square but I am not sure how to get the shape to be symmetrical instead of a swirl cut into the model. Any help on this or advice on how to do a proper swept blend would be greatly appreciated.

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1_valve_hex_socket_1-prt-4.zip

General

P

psobejko

1-Visitor

If you can redefine your square section to have more segments, it gives you way more control than adding in blend vertices in the sweep ui:

Still not quite sure how you can make such a part:

J

jutermohle

Author

1-Visitor

Yes now I understand. Thank you for your help and explanation

D

dgschaefer

21-Topaz II

Here are a few options.

in 1A, I redefined the sketch of the square, much like Paul did, but I added the split to the verticals instead. I then dragged the white dot (circled) for the start point for one curve around to better line things up with the other to eliminate the twist.

In 1b, I simply rotated the white dot on your swept blend, no additional points.

In bb, I created a datum point at the end of your trajectory sketch, lengthened that sketch and then created the transition as a boundary blend and surface cut instead. It creates a nice, even funnel shape, but where it intersects the square hole isn't planar, however.

1_swept_blend.zip

D

dgschaefer

21-Topaz II

OK, I did one more, incase having 6 even splits and a planar intersection with the square hole is important. It's a bit more involved.

First, you have to redefine the square to put vertexes at the 60 degree marks. Split the edges at the centerlines and then, at each corner, use operations > convert to > split on the "L" shapes at the corners (highlighted) to a single entity: