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Best answer by AlanStevens

You an improve the situation with m(t) by multiplying numerator and denominator by exp(-10(t-10)).  For example:

 

g0.jpg

 

Alan

 

2 replies

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StuartBruff23-Emerald V
23-Emerald V
May 2, 2020

It's the exponential in your m(t) expression blowing up.

 

2020 05 02 A.png

 

 

If you want to use B within your program, you'd probably be better of defining it as a local function at the top of the program (B(t)<-m(t)*p

 

Stuart

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StuartBruff23-Emerald V
23-Emerald V
May 2, 2020

Just as a quick follow-up to my previous post, here's one possibility for making Euler a bit easier to use (as it's already tailored to your problem, it's a reasonable option).

 

2020 05 02 B.png

 

Unfortunately, I've only got Prime Express so can't run programs, but you should be able to check it making B return 5 (to behave like your earlier, simpler Euler function).

 

Stuart

K
KhariH1-VisitorAuthor
1-Visitor
May 2, 2020

Right thanks, I know the exp function was going to infinity and mathcad won't handle it. In that same mathcad sheet over off to the right in the worksheet I have another disabled program where I tried to address that issue with an if/else statement. I know the exp blows up around iteration 10 so for k<10 I wanted to calculate m(t) and k>10 just print the 'ms' value. 

A
AlanStevens19-TanzaniteAnswer
19-Tanzanite
May 2, 2020

You an improve the situation with m(t) by multiplying numerator and denominator by exp(-10(t-10)).  For example:

 

g0.jpg

 

Alan

 

    K
    KhariH1-VisitorAuthor
    1-Visitor
    May 2, 2020

    Thank you! I now have a more streamlined program that is at least plotting but the curves just settle around iteration 11. The graphs should look like the image attached. It that program I had a constant value for 'm' but now I want to do one that varies as a function of time.

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