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33 replies

RichardJ19-Tanzanite
19-Tanzanite
June 9, 2016

Variance(a*X)=a^2*Variance(X)

When you calculate the inverse the variance cannot be calculated exactly, but it's approximately Variance(1/X)=Variance(X)/mean(X)^4. The approximation is good as long as the mean is many standard deviations away from 0.

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WalterSchrabmai12-AmethystAuthor
12-Amethyst
June 9, 2016

Richard, thanks. SOrry But I do not mean the Variance but the STANDARD ERROR SE, which is given and wanted.

Moreover I have found this: Could this be also the right answer, I am little confused to compare these two.

ErrorPropagation.gif

gauss1.gif

Gauss2.gif

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RichardJ19-Tanzanite
19-Tanzanite
June 9, 2016

The variance is the square of the standard deviation. The standard errors are standard deviations.

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