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terryhendicott
21-Topaz II
Mar 23, 2024 11:23 PM UTC

Capture.jpg

13 replies

15-Moonstone
Mar 23, 2024 5:36 PM UTC

There are two intermediate solutions. In the end AB=11 in any case 😉

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terryhendicott
21-Topaz II
Mar 23, 2024 11:23 PM UTC
ttokoro
ttokoro21-Topaz IAuthor
21-Topaz I
Mar 24, 2024 1:24 AM UTC

If we use Mathcad it is easy to find the answer. But without sqrt or functions, this puzzle becomes very hard. 

 

image.pngimage.pngimage.png

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t.t.
15-Moonstone
Mar 24, 2024 5:58 AM UTC

This task is not particularly difficult. Students should be able to solve it using the cosine law for side length and the sine formula for the area of a triangle. What is much more interesting about this problem is that solution "11" is possible in two different geometric situations.

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terryhendicott
21-Topaz II
Mar 24, 2024 8:01 AM UTC

Hi,

Prime 9 Express version:

Capture.JPG

Cheers

Terry

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15-Moonstone
Apr 1, 2024 4:00 PM UTC

Additional task: 😉

Given pieces and requirements as usual.

But:

Instead of the given area F=60, the distance AC must now be calculated so that the area of the triangle ABC is maximum. How big is the interior angle at C?

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15-Moonstone
Apr 2, 2024 7:58 AM UTC

Correction:
With the unusual names of the triangle vertices as shown in the sketch in the original problem, the distance AB is logically sought. I accidentally had the usual point designation in my head, where A and B limit the lower side of the triangle and C is the summit.

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Werner_E
25-Diamond I
Apr 5, 2024 12:32 AM UTC

I would solve it that way:

Werner_E_0-1712277132704.png

 

Using Mathcads solving and plotting facilities it may look like this:

Werner_E_0-1712278501328.png

 

Mathcad 15 sheet attached

 

 

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