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aaaaaaaa1-Visitor
1-Visitor
February 10, 2020
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for some vector [25 15 23 20 .. n ] i want to find if the adjacent values exceed 1.2 of each other

  • February 10, 2020
  • 1 reply
  • 4189 views

Hi,

 

I want to write a code where for some vector [25 15 23 20 .. n ] i want to find if the ratios of the adjacent values exceed 1.2 of each other. The output result would be like "Yes" or "No". how do i go about doing that?

 

For example: for vector [15 25 20], because 25/15>1.2, I want the answer as "Yes".

But I would also want the same answer "Yes" if it was [25 15 20] because in this case also for the adjacent values 25/15>1.2.

 

Thanks.

 

Edit1: added "ratios of the"

Edit2: added example

Best answer by Werner_E

Here is a variant which returns just a single answer:

Werner_E_0-1581355629135.png

 

 

1 reply

W
Werner_E25-Diamond I
25-Diamond I
February 10, 2020

Maybe a custom command like the following will do the job:

Werner_E_0-1581347964974.png

 

In case you are using Prime, use "else" instead of "otherwise".

 

    A
    aaaaaaaa1-VisitorAuthor
    1-Visitor
    February 10, 2020

    I'm so sorry that i mistyped the question. 

     

    For example: for vector [15 25 20], because 25/15>1.2, I want the answer as "Yes".

    But I would also want the same answer "Yes" if it was [25 15 20] because in this case also for the adjacent values 25/15>1.2.

     

    Thanks for your reply

     

    W
    Werner_E25-Diamond I
    25-Diamond I
    February 10, 2020

    OK, so its the Ratio, not the difference.

    And what do you expect as a result? Just one single "Yes" or "No" for the whole Vector if the Ratio of any adjacent pair exceeds 1.2, or a "Yes" or "No" for every triple (or pair?) in the Vector?

    If the latter - what about the ends? Do you expect an  n x 1 vector, an  (n-1) x 1 vector or an  (n-2) x 1 vector as a result?

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