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Best answer by Werner_E
@kenan2 wrote:

Okay is it possible to find a solution in the interval [pi ; 2*pi] ? 

If you tell Prime via an "assume" statement it should deliver what you demand. In case of your (unsimplified) expression Prime/muPad has difficulties finding a solution so we can help a little by splitting the task into two parts:

Werner_E_0-1577480218494.png

You may experiment by adding "simplify" and/or "rewrite,asin" at the end of the second symbolic eval to see the very same result written in different ways.

 

BTW, this is another example where the new symbolic in Prime 6 fails to find a solution.

 

 

1 reply

W
Werner_E25-Diamond I
25-Diamond I
December 27, 2019

Keep in mind that sqrt(x^2)=x is only valid if we can assume that x>0.

 

So in your result a and t cancel only if we assume that both are real and >0.

Werner_E_0-1577458005508.png

 

    K
    kenan21-VisitorAuthor
    1-Visitor
    December 27, 2019

    Okay is it possible to find a solution in the interval [pi ; 2*pi] ? 

    W
    Werner_E25-Diamond IAnswer
    25-Diamond I
    December 27, 2019
    @kenan2 wrote:

    Okay is it possible to find a solution in the interval [pi ; 2*pi] ? 

    If you tell Prime via an "assume" statement it should deliver what you demand. In case of your (unsimplified) expression Prime/muPad has difficulties finding a solution so we can help a little by splitting the task into two parts:

    Werner_E_0-1577480218494.png

    You may experiment by adding "simplify" and/or "rewrite,asin" at the end of the second symbolic eval to see the very same result written in different ways.

     

    BTW, this is another example where the new symbolic in Prime 6 fails to find a solution.

     

     

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