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Adlil1-Visitor
1-Visitor
April 8, 2022
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I use different method to get same answers but one of the method did not working.

  • April 8, 2022
  • 1 reply
  • 2745 views

Hello PTC fam,
I'm quite in a bind here where as my result in pic 1 doesn't give the same answer like pic 2 and pic 3. Here I attached my pictures in program. I don't know where I did wrong since it suddenly have the "i" thing there. Thanks in advance.
Regards,
Adlil

Best answer by StuartBruff
@Adlil wrote:

Hello PTC fam,
I'm quite in a bind here where as my result in pic 1 doesn't give the same answer like pic 2 and pic 3. Here I attached my pictures in program. I don't know where I did wrong since it suddenly have the "i" thing there. Thanks in advance.
Regards,
Adlil

I'm not sure that you did anything wrong.  I haven't got Mathcad 15, but converting it to Mathcad Prime 8 shows the same result for all 3 versions.

 

The "i" is simply the imaginary number, indicating that method 1 (pic 1) is returning a complex number.  I suspect that this is due to the way that Mathcad 15 calculates root.  Given that it's a numerical method, there is probably some round-off error that makes root think there is a very small imaginary component - in the order of 10^-13 or so.   Change the number of decimal places that you're showing and see if that shows some trailing digits (other than zero!).

 

Another thing to try is using the symbolic processor (you'll need to add a pair of limit values, say 0 and 1, to root).

 

Here's what Mathcad Prime 8 shows for 15-digits (the imaginary element doesn't show for 4 or 5 digits in Prime😞

 

2022 04 08 a.png

 

Stuart

 

(PS - please use the "Insert Photos" button to add pictures to a message.  This will (should) automatically display the images in the text, thus making it easier for the reader to see them)

1 reply

S
StuartBruff23-Emerald VAnswer
23-Emerald V
April 8, 2022
@Adlil wrote:

Hello PTC fam,
I'm quite in a bind here where as my result in pic 1 doesn't give the same answer like pic 2 and pic 3. Here I attached my pictures in program. I don't know where I did wrong since it suddenly have the "i" thing there. Thanks in advance.
Regards,
Adlil

I'm not sure that you did anything wrong.  I haven't got Mathcad 15, but converting it to Mathcad Prime 8 shows the same result for all 3 versions.

 

The "i" is simply the imaginary number, indicating that method 1 (pic 1) is returning a complex number.  I suspect that this is due to the way that Mathcad 15 calculates root.  Given that it's a numerical method, there is probably some round-off error that makes root think there is a very small imaginary component - in the order of 10^-13 or so.   Change the number of decimal places that you're showing and see if that shows some trailing digits (other than zero!).

 

Another thing to try is using the symbolic processor (you'll need to add a pair of limit values, say 0 and 1, to root).

 

Here's what Mathcad Prime 8 shows for 15-digits (the imaginary element doesn't show for 4 or 5 digits in Prime😞

 

2022 04 08 a.png

 

Stuart

 

(PS - please use the "Insert Photos" button to add pictures to a message.  This will (should) automatically display the images in the text, thus making it easier for the reader to see them)

    A
    Adlil1-VisitorAuthor
    1-Visitor
    April 8, 2022

    Omg, thank you so much. I just did like you suggest and get the answer exactly like the other method. It seems I just need to add limit values. I think it happens with imaginary number because it got no limit and calculate for all possibilities (not sure if my understanding is correct or not). Thanks a bunch. Appreciate it.

      S
      StuartBruff23-Emerald V
      23-Emerald V
      April 8, 2022
      @Adlil wrote:

      Omg, thank you so much. I just did like you suggest and get the answer exactly like the other method. It seems I just need to add limit values. I think it happens with imaginary number because it got no limit and calculate for all possibilities (not sure if my understanding is correct or not). Thanks a bunch. Appreciate it.

      No worries.  Yes, root will likely examine a larger solution space and end up with a "good enough" solution when approaching the "correct" answer from somewhere in the complex plane (off the real axis).   As you say, adding the limits constrains the solution space.

       

      Stuart

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