Jacobi method - show all the partial solution of the sys. iteration by iteration

Forum|Forum|6 years ago
June 11, 2020
2 replies
6548 views

Hello,

I want to out put all the partial solution of the sys. iteration by iteration in a table (or m x n matrix):

itr x1 x2 x3 x4

0 ... ... .... ....

1 .... .... .... ....

- - - - - - - - - - - - - - - - -

itr .... .... .... ....

Also i don't know why in my file does not accept itr->0 instead accept begining from itr->1. I attached the file.

1_jacobi_r12.zip

L

LucMeekes

23-Emerald IV

You've set ORIGIN:=1, this means that indexing in arrays and matrices starts at 1, not 0.

Success!
Luc

W

Werner_E

25-Diamond I

@tubar wrote:

Also i don't know why in my file does not accept itr->0 instead accept begining from itr->1. I attached the file.

Because you have set ORIGIN to be 1 at the top of your sheet and you use x[itr in your program. itr=0 would mean an invalid array index if ORIGIN=1 and thats exactly what the error messages says.

T

tubar

Author

1-Visitor

That one related to the ORIGIN is the minor problem. I take it as it is. Instead, the biggest problem that I still not solved is related to the OUTPUT : iteration vs partial solution of the system. I cannot make the function/file to group all iteration solutions in a table or a matrix. The file is attached in the previous messaje.