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1-Visitor
November 13, 2016
Solved

Loop with error "This value must be a matrix"

  • November 13, 2016
  • 3 replies
  • 2351 views

Hello,

I hope, this is the right thread.

Could someone explain me, what I have to do with this loop.

I want to get F as a (3,4) Matrix.

Thank you for helping ...

Loop with error.png

Best answer by LucMeekes

The offending statement:

Is assigning f to u, rather than to the element on row v and coumn u of F. I guess it should be :

Then you have a funny index '.q.v' for M in the row above.

Can you post the worksheet?

Luc

3 replies

LucMeekes23-Emerald IVAnswer
23-Emerald IV
November 14, 2016

The offending statement:

Is assigning f to u, rather than to the element on row v and coumn u of F. I guess it should be :

Then you have a funny index '.q.v' for M in the row above.

Can you post the worksheet?

Luc

mstoehr-21-VisitorAuthor
1-Visitor
November 14, 2016

You're right Luc, I haven't seen it

Thank you.

M.q.v ist a literal index q for M with a field index v. Do you see any problem with it?

But everything seem workings right now.

Michael

23-Emerald IV
November 14, 2016

Not immediately. If it works it works...

Apparenly you have a Matrix M, 3x4 elements,

and a Vector M..q, of 4 elements.

Luc