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11-Garnet
October 11, 2022
Solved

Mathcad math solve question

  • October 11, 2022
  • 1 reply
  • 2448 views

Hi experts,

 

Can Mathcad solve the below equation? 

 

Jason_power_0-1665501770550.png

because I would like to get the result like the below table, but I don't have any idea how to solve equation 19.

 

for example, when the coordinates are (0.48, 0.15), the result should be 0.653629. but I think my equation has an issue in there, so the result is wrong.

Jason_power_2-1665501981855.png

 

Jason_power_1-1665501814381.png

 

 

Could you please give me some ideas?

Best answer by Werner_E

I


@J_power wrote:

@Werner_E ,

 

Ok, I think I know what to do.
by the way?

Can you tell me how you type the bar on it?

 


The complex conjugate operator can be applied by typing the double quotes " as Luc already wrote.

You may also look it up in the Mathcad help

Werner_E_0-1665591066698.png

 

1 reply

25-Diamond I
October 11, 2022

Obviously you DON'T want to SOLVE an equation but rather want to numerically evaluate an expression.

I notice the conjugate operator in your Eq.9 and I guess the i and j are unit vectors in orthogonal directions so H may be a vector whose absolute value is 0.65...

Would any of the following help?

Werner_E_0-1665528850779.png

Your screenshots don't show how the coordinates should affect the value you are looking for.

 

BTW, if you set t := 0.01 + 0.01 i, the last expression returns 0.653629, exactly the value which is listed in your table as calculated value ...

 

J_power11-GarnetAuthor
11-Garnet
October 12, 2022

May I know how you type the vector?

 

I also try to set t = 0.01+0.01i but the result is not 0.653629.

Can you tell me how you do that?

25-Diamond I
October 12, 2022

Here you are ..

Werner_E_2-1665583196726.png

 

 

file attached

A vector/matrix is created by typing Ctrl-M

 

I don't know if my suggesting concerning H being a vector does make sense. But if, then you could also create it in a way more similar to what we see in your pic of equation (19)

Werner_E_1-1665583023524.png

A more straightforward way would be

Werner_E_3-1665583756796.png