Skip to main content
C
Cornel19-Tanzanite
19-Tanzanite
February 7, 2023
Solved

Newton-Raphson Method - MC Prime 8

  • February 7, 2023
  • 3 replies
  • 2291 views

Hello,

CornelBejan_0-1675757402203.png

 

MC Prime 8 file attached.

Thank you.

 

Best answer by ttokoro

Chage xi-1 - and -> to = 

 

image.pngimage.pngimage.pngimage.png

3 replies

A
AlanStevens19-Tanzanite
19-Tanzanite
February 7, 2023

As Newton-Raphson is essentially numeric there is little point in using a symbolic equals.  Just stick with numerics.

Here is my equivalent using Mathcad 8 Express:

NewtonRaphson.png

Alan

 

    ttokoro
    21-Topaz I
    ttokoro21-Topaz IAnswer
    21-Topaz I
    February 7, 2023

    Chage xi-1 - and -> to = 

     

    image.pngimage.pngimage.pngimage.png

    t.t.
      W
      Werner_E25-Diamond I
      25-Diamond I
      February 7, 2023

      As Alan I am asking what the idea of a symbolical evaluation of the intermediate results of a numerical approximation algorithm might be!!

      Whats wrong with

      Werner_E_0-1675774221497.png

      BTW you had a wrong sign in your implementation of the Newton algorithm. See Alan's approach for a correction.

      Werner_E_1-1675774279121.png

       

      Here is the (unsimplified) symbolic result with four iteration steps.

      Werner_E_2-1675774305627.png

      Are you sure that you really want to see the result for 5 or more steps? 🙂

      Using "simplify" or "simplify, max" may give you a more compact result at the cost of a lot of coffee to drink while  waiting for the calculation to finish.

      But again, what's the sense of displaying those results symbolically?

      W
      Werner_E25-Diamond I
      25-Diamond I
      February 7, 2023

      If you really need to see the symbolic representation of the fifth iteration step, here it is

      Werner_E_0-1675775143985.png

       

      And for an exact symbolic result

      Werner_E_0-1675775914458.png

      😄

       

       

      Terms & ConditionsAccessibility statement